Find the midpoint of H(13,8) and X(-6,-6)

1 answer:

5 0

$coordinates\ of\ midpoint \ M(x,y)\\\\ 
endpoint:\ A(13,8)\\
endpoint:\ B(-6,-6) \\\\ 
M(x,y)=(\frac{x_A+x_B}{2}\ ;\ \frac{y_A+y_B}{2})\\\\
M=(\frac{13-6}{2},\frac{8-6}{2})\\\\
M=(3.5;1)$

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