Question

Find the midpoint of H(13,8) and X(-6,-6)

Answer 1

$coordinates\ of\ midpoint \ M(x,y)\\\\ endpoint:\ A(13,8)\\ endpoint:\ B(-6,-6) \\\\ M(x,y)=(\frac{x_A+x_B}{2}\ ;\ \frac{y_A+y_B}{2})\\\\ M=(\frac{13-6}{2},\frac{8-6}{2})\\\\ M=(3.5;1)$