Y = mx + c
m = 2
y = 2x + c
At (5, 0)
0 = 2(5) + c
c = -10
y = 2x - 10
Answer:
all work is shown and pictured
no real solutions
The conditions for the discriminant are
• If b² - 4ac > 0 then 2 real and distinct roots
• If b² - 4ac = 0 then 2 real and equal roots
• If b² - 4ac < 0 then no real solutions
Answer:
Step-by-step explanation:
Well, the 1 is in the tens place. Soooo then you add the three and then add a 0, the answer will be 30% (Sorry if that didn't make sense I tried!)
