Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
38 14+8+16 To get perimeter add all sides
Answer:
Step-by-step explanation:
As per midsegment theorem of a trapezoid,
Segment joining the midpoints of the legs of the of the trapezoid is parallel to the bases and measure half of their sum.
Length of midsegment =
3). MN =
= 14
4). MN =
= 66.5
5). MN =
7 =
14 = AB + 10
AB = 14 - 10
AB = 4
6). 15 =
30 = 5x
x = 6
Answer:
Step-by-step explanation: First right 56 + 96 in factor forms while one factor is the GCF and other is a sum of two numbers they do not have a common factor that all you gotta do right 56 + 96 in factor forms and follow the rest