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krek1111 [17]
3 years ago
6

Is -9 3/8 a rational or irrational number

Mathematics
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

Rational

Step-by-step explanation:

-9 ⅜ = -75/8

Every number which can be written in a fraction of integers is rational.

Integers can be negative too

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In the diagram, line OB bisects angle AOC. Find m angle BOC. Explain your answer.​
klasskru [66]

Answer:

  m∠BOC = 53°

Step-by-step explanation:

The definition of an angle bisector is that it divides an angle into two congruent angles. ∠AOC is divided by angle bisector OB into angles ∠AOB and ∠BOC, hence those two angles are congruent.

  m∠AOB = m∠BOC = 53°

6 0
3 years ago
The difference of two numbers is nine if the larger number is one more than twice the smaller number find a larger number
8_murik_8 [283]

Answer: 6 and 21

Step-by-step explanation:

6 0
3 years ago
Evaluate in 7<br> 0.51<br> 1.95<br> 0.85<br> 1.61
Ber [7]

Answer:

We may log in directly in our scientific calculator the given value ln 7 and get an answer of 1.9459. On the other hand, we can rewrite the expression as,

                            log to the base e or 7 = x

which can be written as,

                              e^x = 7

The value of x from this is still equal to 1.9459.

Step-by-step explanation:

4 0
3 years ago
W+3&gt;9 <br><br> I need to solve this inequality.... I’m not very good at this stuff.
mezya [45]
W+3>9
-3>-3 (getting the variable by its self)

w=6 (answer)
7 0
3 years ago
Finding a polynomial of a given degree with given zeros
galben [10]

Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)

One of them is real and the other two are complex conjugate roots

Since the real root is 4, then

x = 4

Since the complex root is (1 - i), then

The other root will be the conjugate of it (1 + i)

x = (1 - i)

x = (1 + i)

To find f(x) we will multiply the three factors of it

We can get the factors from the zeroes

x=4

Subtract 4 from both sides

\begin{gathered} x-4=4-4 \\ x-4=0 \end{gathered}

The first factor is (x - 4)

\begin{gathered} x=1-i \\ x-(1-i)=(1-i)-(1-i) \\ x-1+i=0 \end{gathered}

The second factor is (x - 1 + i)

The third factor is (x - 1 - i)

f(x)=(x-4)(x-1+i)(x-1-i)

We will multiply them to find f(x)

\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}

Multiply it by (x - 4)

\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}

The answer is

f(x)=x^3-6x^2+10x-8

5 0
1 year ago
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