Answer:
281 cups
Step-by-step explanation:
2000-1719= 281
D it's undefined because it has no where else to go.
Answer:
25.10% probability that the spending is between 46 and 49.56 dollars
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 47.67, \sigma = 5.5](https://tex.z-dn.net/?f=%5Cmu%20%3D%2047.67%2C%20%5Csigma%20%3D%205.5)
What is the probability that the spending is between 46 and 49.56 dollars?
This is the pvalue of Z when X = 49.56 subtracted by the pvalue of Z when X = 46. So
X = 49.56
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{49.56 - 47.67}{5.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B49.56%20-%2047.67%7D%7B5.5%7D)
![Z = 0.34](https://tex.z-dn.net/?f=Z%20%3D%200.34)
has a pvalue of 0.6331
X = 46
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{46 - 47.67}{5.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B46%20-%2047.67%7D%7B5.5%7D)
![Z = -0.3](https://tex.z-dn.net/?f=Z%20%3D%20-0.3)
has a pvalue of 0.3821
0.6331 - 0.3821 = 0.2510
25.10% probability that the spending is between 46 and 49.56 dollars
Answer:
14.25 packs per hour
Step-by-step explanation:
it is 4 hours from 2:00-5:00 so... 57÷4=14.25 packs per hour