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NNADVOKAT [17]
3 years ago
5

Find the x-intercepts for the parabola defined by this equation

Mathematics
2 answers:
enot [183]3 years ago
6 0

Answer:

Your x-intercepts are (1, 0) and (5, 0)

Step-by-step explanation:

Factor out the expression:

y =x^{2}  -6x +5 factors out to y = (x-1) * (x-5)

Because this factored out form is now in intercept form, we can solve that the two intercepts are (1, 0) and (5, 0).

Phoenix [80]3 years ago
4 0

Answer:

The coordinates are (5 ,0) and (1 ,0)

<em>Answer is </em><em>given below with explanations</em><em>.</em>

Step-by-step explanation:

to \: find \: the \: x \: intercepts \: of \: the \: parabola \:  \\ defined \: by \:  {x}^{2}  - 6x + 5 = y \\ let \: y = 0 \\ then \\   {x}^{2}  - 6x + 5 =0 \\ by \: factorization \\ (x - 5)(x - 1) = 0 \\ x - 5 = 0 \:  \: (or )\: x - 1 = 0 \\ x = 5 \:  \: (  or) \: x = 1

We want ti express the intercepts as two ordered pairs (y = 0)

Then the coordinates are (5 ,0) and (1 ,0)

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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