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Alchen [17]
3 years ago
11

Compare the two fractions. Use >, <, or =. 4/6 [ ] 6/10

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
4 0
\dfrac{4}{6}=\dfrac{4\cdot5}{6\cdot5}=\dfrac{20}{30}\\\\\dfrac{6}{10}=\dfrac{6\cdot3}{10\cdot3}=\dfrac{18}{30}\\\\\dfrac{20}{30} > \dfrac{18}{30}\\\\therefore\ \dfrac{4}{6} > \dfrac{6}{10}
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I need help plssssssssss
drek231 [11]

We can say that the area of the figure equals...

5.5 by 9 rectangle - 2 by 2 triangle - 2 by 5 triangle - 9 by 3.5 triangle

5.5 by 9 rectangle = 5.5 x 9 = 49.5 un²

2 by 2 triangle = 1/2 x 2 x 2 = 2 un²

2 by 5 triangle = 1/2 x 2 x 5 = 5 un²

9 by 3.5 triangle = 1/2 x 9 x 3.5 = 15.75 un²

area of figure = 49.5 un² - 2 un² - 5 un² - 15.75 un² = 26.75 un²

answer: 26.75 un²

5 0
4 years ago
Read 2 more answers
Solve 5/7x=-25<br> The solution is x= ?
Bad White [126]
The answer To this is x=-35
4 0
3 years ago
Please answer this. thank you
Rama09 [41]

Answer:  (-\infty, -4]

Curved parenthesis at negative infinity

Square bracket at -4

====================================================

Work Shown:

5(x+4) \le 0 \\\\x+4 \le \frac{0}{5} \\\\x+4 \le 0 \\\\x \le 0-4 \\\\x \le -4 \\\\

The last inequality shown above is the same as saying -\infty < x \le -4

Converting this to interval notation leads to the final answer of (-\infty , -4]

Note the use of a square bracket at -4 to include this endpoint. We can never include either infinity, so we always use a parenthesis for either infinity.

5 0
3 years ago
Use a calculator to solve the following equation for θ on the interval [−90∘,90∘]. Sin(θ)=34
exis [7]

The value of θ from the given equation is 48.59degrees

<h3>Trigonometry identity</h3>

Given the trigonometry function

Sin(θ)=3/4

We are to find the value of theta that will make the expression true

Take the arcsin of both sides

arcsin Sin(θ)= arcsin(3/4)

θ = arcsin(3/4)

θ = 48.59

Hence the value of θ from the given equation is θ = 48.59 defense

Learn more on trig identity here:brainly.com/question/7331447

4 0
3 years ago
How would I find the diameter?
adell [148]
By measuring the width of the circle or sphere radius is half of the diameter
3 0
3 years ago
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