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3 years ago

What is the multiplicative rate of change of the exponential function shown on the graph?

Mathematics

2 answers:

ivanzaharov [21]3 years ago

7 0

Answer:

Option: D is correct.

9/2

Step-by-step explanation:

We have to find the multiplicative rate of change of the exponential function shown on the graph.

We know that a general exponential function is given as:

$y=ab^x$

where b is the multiplicative rate of change.

Now when x=0 we have y=1.

i.e. 1=a

Hence, a=1

and y=b^x

Also,

the graph passes through (1,9/2)

Now when x=1 we have y=9/2

i.e.

9/2=b

Hence, the multiplicative rate of change is:

9/2

vova2212 [387]3 years ago

5 0

...........................................Answer is D

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What is the constant of proportionality?

Damm [24]

Answer: B) 18

=========================================================

Explanation:

x = number of packs of yogurt (column 1)

y = number of ounces of yogurt (column 2)

To get the constant of proportionality k, we divide y over x

k = y/x

k = 36/2 = 18 .... from row 1

k = 54/3 = 18 ... from row 2

k = 90/5 = 18 .... from row 3

This k = 18 value means that each time x goes up by 1, the value of y goes up by 18. This is the slope of the line y = 18x, so it represents the rate of change.

Put another way: 1 pack of yogurt is 18 ounces

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3 years ago

How much salt is in a mixture containing 10 gal of an 11% salt solution and 6 gal of a 7% salt solution

Helga [31]

In a 10 gal of an 11% salt solution,

11% of 10 gal are sal.

11% *10 gal=(11/100)*10 gal =0.11*10 gal = 0.1 gal is salt.

Similarly, 0.07*6 gal= 0.42 gal is salt of the 6 gal in the second solution.

The mixture is 10 gal +6 gal = 16 gal, and contains a total of

0.1 gal +0.42 gal = 0.52 gal of salt.

0.52 = x% of 16

0.52=x%*16

x=(0.52/16)*100=0.0325*100=3.25

Answer: there is 0.52 gal of salt in the mixture, that is 3.25%

4 0

3 years ago

A child spots crackers in a cabinet at an angle of elevation of 50. The crackers are 3.5 ft above the child. To the nearest tent

zimovet [89]

the horizontal distance between the child and the crackers is 2.9 ft .

Step-by-step explanation:

Here we have , A child spots crackers in a cabinet at an angle of elevation of 50. The crackers are 3.5 ft above the child. We need to find what is the horizontal distance between the child and the crackers . Let's find out:

According to question , we have a right angle triangle with parameters as :

$Perpendicular =3.5\\Base = ?\\x = 50$ , Where x is angle of elevation !