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Damm [24]
3 years ago
7

Which is equivalent to the following expression? (2x^2+4xy-y^2)+(x^2+3xy-y^2)

Mathematics
2 answers:
ss7ja [257]3 years ago
7 0

Answer:

I agree with Lisboa The answer is C

Step-by-step explanation:


Karo-lina-s [1.5K]3 years ago
3 0

Answer C : 3x^2+7xy-2y^2

equivalent to the following expression

(2x^2+4xy-y^2)+(x^2+3xy-y^2)

2x^2+4xy-y^2+x^2+3xy-y^2

Combine like terms

2x^2+x^2+4xy+3xy-y^2-y^2

2x^2 + x^2 is 3x^2

4xy+3xy is 7xy

-y^2-y^2 is -2y^2

So expression becomes

3x^2+7xy-2y^2

Answer  C is correct

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Answer:

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Step-by-step explanation:

<em>~ Part I ~</em>

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<em>~ Part 3 ~</em>

1. The mode is known to be the number repeated most often, and from the previous question we see the numbers arranged in a benficial manner. Now we can straight away see that the number repeated the most is ⇒<em> 95</em>

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