★ Formula Applied :




★ Explanation :

Lets use substitution method ,
Let , u = sin2x
⇒ du = 2.cos2x.dx





★ Alternate Method :




]

It can be said that chivalry affected the characters when the Knights exhibited their behavior. The Green Knight challenged the knights´honor and so Sir Gawain asked the King to accept that challenge. It seems that he wanted to show his loyalty (value of Chivalry) to King Arthur. Later on, the Green Knight promised to keep his word (value of Chivalry).
Answer:
Explanation:
Did you ever get the answer?
A: prefix - beginning
B: root - middle
C: suffix - end
Answer:
Please clarify your question. Thanks!