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Hitman42 [59]
3 years ago
13

The graph of the function f(x) = –(x + 6)(x + 2) is shown below.

Mathematics
1 answer:
laiz [17]3 years ago
4 0

Answer:

Option A. x < -4

Step-by-step explanation:

The given function is f(x) = -(x + 6)(x + 2)

General form of the function will be,

f(x) = -(x² + 2x + 6x + 12)

     = -(x² + 8x + 12)

Vertex form of the function will be,

f(x) = -[x² + 2(4)x + 12]

     = -[(x² + 2(4)x + 16) - 16 + 12]

     = -(x + 4)² + 4

Therefore, parabola for the function above will open down with vertex (-4, 4) as shown in the graph attached.

Graph shows the function is increasing in x < -4 and decreasing in x > -4.

Therefore, Option A. is the correct answer.

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Find the area of the circle. round your answer to the nearest hundredth<br> radius= 2cm
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Answer:

12.57cm

Step-by-step explanation:

Formula : Pi×r²

pi×2²=4pi=12.56637061

rounded : 12.57cm

3 0
3 years ago
1) Solve: – 4x – 11 = 7<br> Pls help
blagie [28]

Answer:

x = -9/2

Step-by-step explanation:

-4x - 11 = 7

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8 0
3 years ago
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denis23 [38]

Answer:

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x−Y=0 <dependent

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Step-by-step explanation:

I haven't learn these type of questions yet only freshman in high so tried to come up with the best answers with a lot of research

Hope this help

5 0
3 years ago
An open metal tank of square base has a volume of 123 m^3
snow_lady [41]

Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

__

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

__

c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

__

d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

3 0
3 years ago
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Answer:

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