At short focusing distances, ciliary muscles contract causing the suspensory ligaments to tighten.
The ciliary muscle is an integral muscle of the eye that is constructed as a ring of smooth muscle in the middle layer of the eye, the uvea (vascular layer). It regulates the passage of aqueous humor into Schlemm's canal and governs accommodation for observing objects at different distances.
A suspensory ligament is a ligament that provides support to a body part, particularly an organ. The suspensory ligament protects the fetlock from hyperextension (i.e., falling too low) during exercise. The ligament begins in both the fore and hindlimbs at its connection to the back of the upper cannon bone.
When the ciliary muscle relaxes, its diameter increases; when the suspensory ligaments tighten, the lens becomes thinner. This occurs when concentrating on a celestial object. When the ciliary muscle contracts, the lens becomes much more circular and has more focusing power because the pressure on the zonular fibers is reduced. When the ciliary muscles relax, these fibers contract, pulling the lens out and creating a flatter shape with less focusing power
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The chemical substance in adult male pig's urine, which can also be found in other mammals, is called Puberty Accelerating Pheromone. It is also found in boar's saliva, and was said to be responsible in inducing early puberty in young female piglets.
Answer:
Glucose Transport
Explanation:
Glucose Transport is a highly regulated process accomplished mostly by facilitated diffusion using carrier proteins to cross cell membranes.
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<span>There are many indicators for predator presence. Some of them are:
Being able to spot predator marks like scratches or fur.
Being able to feel predator movements.
</span><span>Echo-location </span>For example, moths respond to the echo-location calls from their bat predators; moths drop to the ground once they hear the sound pulse from the bat.
Answer:
A 0.015M
Explanation:
Molarity, which refers to the molar concentration of a solution, can be calculated using the formula:
Molarity (M) = mole (n) / volume (L)
Based on the information provided in this question, the solution contains 0.83 g of dissolved KCI.
We can calculate the number of moles of KCl in the solution by using the formula:
Mole = mass ÷ molar mass
Where atomic mass of; K = 39, Cl = 35.5
Molar Mass of KCl = 39 + 35.5
= 74.5g/mol.
Mole = 0.83g/74.5g/mol.
mole = 0.01114
Approximately, n = 0.011mol
Hence, molarity = 0.011mol/0.75L
Molarity = 0.0146
Molarity = 0.015M
