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Reil [10]
3 years ago
12

What is the equation of this graphed line (-6,-3) (6,-7)

Mathematics
2 answers:
PtichkaEL [24]3 years ago
6 0

Answer:  x+3y=-15

Step-by-step explanation:

The equation of a line passes through (a,b) and (c,d) is given by :-

(y-b)=\dfrac{d-b}{c-a}(x-a)

Then, the equation of a line that passes through (-6,-3) (6,-7) will be :-

(y-(-3))=\dfrac{-7-(-3)}{6-(-6)}(x-(-6))\\\\\Rightarrow y+3=\dfrac{-7+3}{6+6}(x+6)\\\\\Rightarrow\ y+3=\dfrac{-4}{12}(x+6)\\\\\Rightarrow\ y+3=\dfrac{-1}{3}(x+6)\\\\\Rightarrow\ 3(y+3)=-x-6\\\\\Rightarrow\ 3y+9=-x-6\\\\\Rightarrow\ x+3y=-15.

Hence, the required equation is x+3y=-15.

Svetradugi [14.3K]3 years ago
5 0
The equation is a linear equation in y=mx+b format. The slope-intercept linear equation for this line would be y=-0.33x-5
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