Question

What is the equation of this graphed line (-6,-3) (6,-7)

Answer 1

Answer:  $x+3y=-15$

Step-by-step explanation:

The equation of a line passes through (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

Then, the equation of a line that passes through (-6,-3) (6,-7) will be :-

$(y-(-3))=\dfrac{-7-(-3)}{6-(-6)}(x-(-6))\\\\\Rightarrow y+3=\dfrac{-7+3}{6+6}(x+6)\\\\\Rightarrow\ y+3=\dfrac{-4}{12}(x+6)\\\\\Rightarrow\ y+3=\dfrac{-1}{3}(x+6)\\\\\Rightarrow\ 3(y+3)=-x-6\\\\\Rightarrow\ 3y+9=-x-6\\\\\Rightarrow\ x+3y=-15.$

Hence, the required equation is $x+3y=-15$.

Answer 2

The equation is a linear equation in y=mx+b format. The slope-intercept linear equation for this line would be y=-0.33x-5