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3 years ago

Does anyone know how to do this. that can please show me the work ?? -view attachment

Mathematics

1 answer:

suter [353]3 years ago

6 0

SOH CAH TOA
Sine=opposite leg/hypotenuse
Cosine=adjacent leg/hypotenuse
Tangent=opposite leg/adjacent leg
SOH CAH TOA
So d is the correct answer

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the number to which a base is raised to is called the __. this tells you how many times to multiply the base together

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A quadratic function is a function of the form y=ax^2+bx+c where a, b, and c are constants. Given any 3 points in the plane, the

pochemuha

Answer:

The quadratic function whose graph contains these points is $y=-x^{2}-2x-2$

Step-by-step explanation:

We know that a quadratic function is a function of the form $y=ax^{2}+bx+c$ . The first step is use the 3 points given to write 3 equations to find the values of the constants a,b, and c.

Substitute the points (0,-2), (-5,-17), and (3,-17) into the general form of a quadratic function.

$-2=a*0^{2}+b*0+c\\c=-2$

$-17=a*-5^{2}+b*-5+c\\c=-25a+5b-17$

$-17=a*3^{2}+b*3+c\\ c=-9a-3b-17$

We can solve these system of equations by substitution

Substitute $c=-9a-3b-17$

$-9a-3b-17=25a+5b-17\\-9a-3b-17=-2$

Isolate a for the first equation

$-9a-3b-17=-25a+5b-17\\a=\frac{b}{2}$

Substitute $a=\frac{b}{2}$ into the second equation

$-9\left(-\frac{b}{2}\right)-3b-17=-2$

Find the value of b

$-9\left(-\frac{4b}{17}\right)-3b-17=-2\\ b=-2$

Find the value of a

$a=\frac{b}{2}\\ a=-1$

The solutions to the system of equations are:

b=-2,a=-1,c=-2

So the quadratic function whose graph contains these points is

$y=-x^{2}-2x-2$

As you can corroborate with the graph of this function.

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3 years ago

(x - 2)² + 6x – 7 Which of the following is equivalent to

podryga [215]

Answer:

$x^2 +2x-3$

Step-by-step explanation:

Given

$(x - 2)\² + 6x - 7$

Required

The equivalent

We have:

$(x - 2)\² + 6x - 7$

Expand

$(x - 2)\² + 6x - 7 = x^2 -2x-2x +4 +6x - 7$

Collect like terms

$(x - 2)\² + 6x - 7 = x^2 -2x-2x+6x +4 - 7$

$(x - 2)\² + 6x - 7 = x^2 +2x-3$

Hence, the equivalent is:

$x^2 +2x-3$

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3 years ago

How do you write r2/3 t1/3 in radical form?

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I hope this helps you

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3 years ago

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Akimi4 [234]

Answer:

2 to 9

Step-by-step explanation:

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