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3 years ago

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What is the area of the polygon below

2 answers:

algol133 years ago

5 0

Answer: The correct option is (D) 147 sq. units.

Step-by-step explanation: We Re given to find the area of the polygon shown in the figure.

Let us divide the given polygon in two rectangles A and B as shown in the attached figure below.

The dimensions of rectangle A are

length, l = 10 units and breadth, b = 3 units.

So, the area of rectangle A is given by

$AREA_A=l\times b=10\times3=30~\textup{sq. units}.$

And, the dimensions of rectangle B are

length, l' = 13 units and breadth, b' = 12 - 3 = 9 units.

So, the area of rectangle B is given by

$AREA_B=l'\times b'=13\times9=117~\textup{sq. units}.$

Therefore, the area of the polygon is

$AREA=AREA_A+AREA_B=30+117=147~\textup{sq. units}.$

Thus, the required area of th given polygon is 147 sq. units.

Option (D) is CORRECT.

Fudgin [204]3 years ago

3 0

Separate it into two different shapes

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Suppose x and y vary together such that y = 2 x + 11 . Suppose x varies from x = 2 to x = 8.5 .

Stells [14]

Answer:

a) x changes by 6.5 units

b) y changes by 13 units

Step-by-step explanation:

a. Over this interval, how much does x change by?

Initially, we have that x = 2.

In the end, we have that x = 8.5.

So x changes by 8.5-2 = 6.5 units

b. Over this interval, how much does y change by?

Initially, when x = 2, we have that y = 2x + 11 = 2*2 + 11 = 15

In the end, when x = 8.5, we have that y = 2*8.5 + 11 = 28

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3 years ago

Find the length of RA. A. 42 B. 84 C. 14 D. 7

fiasKO [112]

Answer:

$\large \boxed{\mathrm{B. \ 84}}$

Step-by-step explanation:

$LU$ bisects $RU$ and $UA$ .

$RU=UA$

$3m+21=6m$

Solve for m.

Subtract 3m from both sides.

$21=3m$

Divide both sides by 3.

$7=m$

Calculate $RA$ .

$RA=3m+21+6m$

$RA=9m+21$

Put m = 7.

$RA=9(7)+21$

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3 years ago

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Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)

natima [27]

$\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}$

$x^3=x\cdot x^2$ , and $x(x^2+2x+1)=x^3+2x^2+x$ . Subtracting this from the numerator gives a remainder of

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3 years ago

Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>

sladkih [1.3K]

Answer:

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$\theta$ = 60°
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$\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2$

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