<span>P(1 claim) = p/4
P(2 claims) = (p/4)/4 = p/16
You should see that the distribution follows a geometric series with common ratio 1/4.
Sum geometric = (first term) / (1 - common ratio) = p/(1 - 1/4) = 4p/3
But the sum of all the probabilites must equal 1 ----> 4p/3 = 1 ----> p = 3/4
P(2 or more claims) = 1 - P(0 claims) - P(1 claim) = 1 - 3/4 - 3/16 = 1/16</span>
Answer:
The ratio of AC/CB=1/3
Step-by-step explanation:
We use the section formula:

We substitute the point A(-1.5,0) and B(4.5,8).
We plug in the points to get:

This is supposed to be equal to: (0,2).

We can equate, corresponding coordinates to find m and n.

This implies that:




Therefore the ratio is m:n=1:3
I think
J,BB,S
(I shortened name to letter)