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Ghella [55]
3 years ago
11

Write a word problem with 16 for the product

Mathematics
1 answer:
nadezda [96]3 years ago
6 0

Kate wants to give out 4 chocolates to each person in her family for Valentine's Day. If there are 4 people in the family, how many chocolates would he have to buy?
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Select all the irrational numbers
tiny-mole [99]

Answer:

A and E would be your answer

Step-by-step explanation:

5 0
2 years ago
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How does the graph of the function g(x) = 5x + 1 differ from the graph of f(x) = 5*?
elena-14-01-66 [18.8K]

Answer:

C. It is translated up 1 unit.

Step-by-step explanation:

Translations of a function f(x)

To translate a function f(x) a units to the right, we have f(x-a)

To translate a function f(x) a units to the left, we have f(x+a)

To translate a function f(x) a units up, we have f(x) + a

To translate a function f(x) a units down, we have f(x) - a

In this question:

g(x) = 5x + 1

f(x) = 5x

This means that the function g(x) is 1 added to the function f(x), that is, it is translated up 1 units, and the correct answer is given by option c.

7 0
3 years ago
Ms.Ambrose paid $10 for 1.25 pounds of almonds. How much did the almost cost per pound
love history [14]

Answer:

A

Step-by-step explanation:

10 divided by 1.25=8

7 0
3 years ago
Read 2 more answers
Lusa sells stuffed animals. She sells a stuffed elephant for $34.90, and the sales tax is 9% of the sale price About how much
viktelen [127]

Answer:

3.14

Step-by-step explanation:

8 0
3 years ago
Math help Please!!!!
GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation  −2y=3x+7 in the form y=-\dfrac{3}{2}x-\dfrac{7}{2}. Here the slope of the given line is  m_1=-\dfrac{3}{2}. If m_2 is the slope of perpendicular line, then

m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.

Answer 1: \dfrac{2}{3}

Part B. The slope of the line y=−2x+3 is -2. Since -\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2, then lines from part A are not parallel to line a.

Since -2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1, both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line y=\dfrac{x}{4}+5 is \dfrac{1}{4}. Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then

7=-4·2+b,

b=7+8,

b=15.

Answer 4: y=-4x+15.

Part E. Consider vectors \vec{p}_1=(-c-0,0-(-d))=(-c,d)\quad \text{and}\quad \vec{p}_2=(0-b,a-0)=(-b,a). These vectors are collinear, then

\dfrac{-c}{-b}=\dfrac{d}{a},\quad \text{or}\quad -\dfrac{a}{b}=-\dfrac{d}{c}.

Answer 5: -\dfrac{a}{b}=-\dfrac{d}{c}.

5 0
4 years ago
Read 2 more answers
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