ANSWER
Frequency=2
Midline =3
Amplitude =5
Period =π
EXPLANATION
We have:
The given function is of the form;
where
a=|5| =5 is the amplitude
and b=2 is the frequency.
and 2π/b=2π/2=π
The range of the given function is
8≤y≤-2
The midline is
Which is a point on the circle whose center is (0, 0) and whose radius is 5?
1 answer:
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Start by simplifying the exponent.
(4 units)³ is equal to (4 units) (4 units) (4 units) or 64 units³.
So we have .
Next, we multiply (4/3)(64) which can
be thought of as (4/3)(64/1)
So multiplying across the numerators and across the denominators,
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