All categories

2 years ago

Which is a point on the circle whose center is (0, 0) and whose radius is 5?

1 answer:

5 0

Circle equation is given in the form of (x-a)²+(y-b)² = r²

Where (a, b) is the centre and 'r' is the radius

We have a circle with centre (0, 0) and radius of 5.

Substituting these value into the equation form, we have

(x-0)²+(y-0)² = 5²
x² + y² = 25

Hence, the equation of the circle is x² + y² = 25

You might be interested in

Please help question in the picture

Tju [1.3M]

We can think of this as a right triangle, where the given lengths are the legs.

So, we can solve using the Pythagorean Theorem.

21² + 28² = c²

441 + 784 = c²

1225 = c²

35 = c

35 miles

8 0

2 years ago

4. A map has a scale of 1 inch = 100 miles. The distance between two cities is 7.25 inches. If a car travels

motikmotik

Answer:

14.5 hours/14 hours 30 minutes

Step-by-step explanation:

The distance between the two cities is 7.25•100=725 because you multiply the scale distance by the scale.
The number hours is 725/50=14.5 hours because you divide the distance by 50 (the miles per hour).

4 0

2 years ago

Part C

Doss [256]

Answer:

ANSWER. Part c

Line segment PM = 4.2 length

ML = 6.2

ON = 3

NK = 2

Step-by-step explanation:

MRK ME BRAINLIEST PLZZZZZZZ

5 0

2 years ago

Graph by using the slope and the y intercept.

Mashutka [201]

1. a) equation of the line :

$y = \dfrac{2}{5}x - 7$

y - intercept = -7

so, it will pass through point (0, -7)

and if we plug the value of x as 5, we get

$y = (\dfrac{2}{5} \times 5) - 7$

$y = 2 - 7$

$= - 5$

so, it will pass through point (5, -5) too

now, just plot the points (0 , -7) and (5 , -5) and join them.

2. b) equation of line is :

$y = - 3x + 5$

here, y - intercept = 5

so the line passes through point (0 , 5)

now, Plugging the value of x = 1 we get :

$y =( - 3 \times 1) + 5$

$y = - 3 + 5$

$y = 2$

so, the given line passes through point (1 , 2)

plotting the points, we can get our required line.

6 0

2 years ago

Write functions for each of the following transformations using function notation. Choose a different letter to represent each f

kupik [55]

Answer:

$(a)\ T_{a,b} =(x +a,y+b)$

$(b)\ F_{y\ axis} = (-x,y)$

$(c)\ F_{x\ axis} = (x,-y)$

$(d)\ R_{o,90^o} = (-y,x)$

$(e)\ R_{o,180^o} = (-x,-y)$

$(f)\ R_{o,270^o} = (y,-x)$

Step-by-step explanation:

Solving (a): Translate a units right, b units up

When a function is translated a units right, the number of units will be added to the x coordinate

When a function is translated b units up, the number of units will be added to the y coordinate.

So, we have:

$T_{a,b} =(x +a,y+b)$

Solving (b): Reflect across y-axis

When a function is translated across the y-axis, the x coordinate gets negated.

So, we have:

$F_{y\ axis} = (-x,y)$

Solving (c): Reflect across x-axis

When a function is translated across the x-axis, the y coordinate gets negated.

So, we have:

$F_{x\ axis} = (x,-y)$

Solving (d): 90 degrees rotation counterclockwise

When a function is rotated 90 degrees counterclockwise, the y-coordinates gets negated and then swapped with the x-coordinate.

So, we have:

$R_{o,90^o} = (-y,x)$

Solving (e): 180 degrees rotation counterclockwise

When a function is rotated 180 degrees counterclockwise, the coordinates are negated.

So, we have:

$R_{o,180^o} = (-x,-y)$

Solving (f): 270 degrees rotation counterclockwise

When a function is rotated 270 degrees counterclockwise, the x-coordinates gets negated and then swapped with the y-coordinate.

So, we have:

$R_{o,270^o} = (y,-x)$

6 0

2 years ago