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Molodets [167]
3 years ago
13

Prove that the value of the expression 12^5+12^4 is divisible by 13.

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

20736

Step-by-step explanation:

<u>Step 1:  Simplify the exponents</u>

12^5 = 248832

12^4 = 20736

<u>Step 2:  Add them together</u>

248832 + 20736

269568

<u>Step 3:  Divide the number by 13</u>

269568 / 13

20736

Answer:  20736

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Let A be a 3 by 6 , B be a 6 by 7 and C be a 7 by 3 matrix. Determine the size of the following matrices (if they do not exist,
kozerog [31]

Answer:

a. AB: 3 by 7

b. BA: N by N

c. A^TB: N by N

d. BC: 6 by 3

Step-by-step explanation:

Given

A =3\ by\ 6

B =6\ by\ 7

C =7\ by\ 3

Required

The dimension of the following matrices

As a general rule:

For A * B to be successful, the columns in a must equal the rows in B

Using this rule, we have:

A_{m*n} * B_{n * p} = AB_{m*p}

So:

(a)\ AB

A_{3*6} * B_{6*7} \to AB_{3 * 7}

(b)\ BA

B_{6*7} * A_{3*6} \to AB_{N * N}

The column numbers of B does not equal the row numbers of A.

Hence, BA does not exist

(c)\ A^TB

A^T implies that:

If A =3\ by\ 6, then

A^T = 6\ by\ 3

So:

A^T_{6*3} * B_{6,7} \to A^TB_{N*N}

The column numbers of A^T does not equal the row numbers of B.

Hence, A^TB does not exist

(d)\ BC

B_{6*7} * C_{7*3} \to BC_{6,3}

6 0
3 years ago
The Wilson family had 5 children. Assuming that the probability of a child being a girl is 0.5, find the probability that the Wi
Dafna11 [192]

Answer:

0.813

0.500

Step-by-step explanation:

Use binomial probability.

P = nCr p^r q^(n−r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1−p).

In this problem, n = 5, p = 0.5, and q = 0.5.

"At least 2 girls" means r = 2, 3, 4, or 5.

Or, we can use the complement.

P(at least 2 girls) = 1 − P(at most 1 girl)

P(at least 2 girls) = 1 − P(r=0 or r=1)

P(at least 2 girls) = 1 − ₅C₁ (0.5)¹ (0.5)⁵⁻¹ − ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰

P(at least 2 girls) = 1 − 5 (0.5) (0.5)⁴ − 1 (1) (0.5)⁵

P(at least 2 girls) = 1 − 6 (0.5)⁵

P(at least 2 girls) ≈ 0.813

"At most 2 girls" means r = 0, 1, or 2.

P(at most 2 girls) = P(r=0, r=1, or r=2)

P(at most 2 girls) = ₅C₀ (0.5)⁰ (0.5)⁵⁻⁰ + ₅C₁ (0.5)¹ (0.5)⁵⁻¹ + ₅C₂ (0.5)² (0.5)⁵⁻²

P(at most 2 girls) = 1 (1) (0.5)⁵ + 5 (0.5) (0.5)⁴ + 10 (0.5)² (0.5)³

P(at most 2 girls) = 16 (0.5)⁵

P(at most 2 girls) = 0.500

4 0
3 years ago
The legth of a rectangle is the same as the legth of each side of a square. The legth rectangle is 4 cm more than 3 times the wi
ankoles [38]

Let, length and breadth of rectangle is L and B respectively.

It is given that :

The length rectangle is 4 cm more than 3 times the width of the rectangle.

L = 3B + 4  ......1 )

Also, area of square = area of the rectangle + 66

L² = LB + 66

Putting value of L from

L² = ( 3B + 4 )( B ) + 66

L² = 3B²  + 4B + 66

( 3B + 4 )² = 3B²  + 4B + 66

9B² + 16 + 24B = 3B²  + 4B + 66

6B² + 20B - 50 = 0

3B² + 10B - 25 = 0

3B² + 15B - 5B -25 = 0

3B( B + 5 ) -5( B + 5 ) = 0

B = 5/3 units

L = 3( 5/3 ) + 4

L = 5 + 4 = 9 units

Hence, this is the required solution.

6 0
3 years ago
tell me which 4 letters are correct! A? B? C? D? E? F? if you get them right i will give you brainliest!!
butalik [34]

Answer:

B, E, D, and C

Step-by-step explanation:

5 0
2 years ago
How many multiples of three are between 10 and 787 and show work pls
SOVA2 [1]
787-10=777
777/3=259

259 multiples of 3
8 0
3 years ago
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