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Natalija [7]
3 years ago
15

A gallon of milks sells for $3.18 and a quart of milk sells for $0.76. Which item has the better unit price? Justify your answer

using two different methods.
Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

Second\ price\ that\ is\ 1\ quart\ milk=\$0.76\ has\ better\ unit\ price

Step-by-step explanation:

Use gallon unit:

<u><em>First Price:</em></u>

1\ gallon\ milk=\$3.18\\\\

<em><u>Second Price:</u></em>

<em><u /></em>4\ quart=1\ gallon\\\\1\ quart\milk=\$0.76\\\\4\ quart\ milk=4\times 0.76=\$3.04\\\\\Rightarrow 1\ gallon\ milk=\$3.04<em><u /></em>

<em><u /></em>

<em><u /></em>1\ gallon\ at\ first\ price\ is\ greater\ than\ the\ rate\ of\ 1\ gallon\ at\ second\ price\\\\Hence\ 1\ quart=\$0.76\ has\ the\ better\ unit\ price.<em><u /></em>

<em><u /></em>

Second Method: Use Quart Unit:

<u><em>First Price:</em></u>

1\ gallon=4\ quart\\\\1\ gallon\ milk=\$3.18\\\\4\ quart\ milk=\$3.18\\\\1\ quart\ milk=\frac{3.18}{4}=\$0.795

<u><em>Second Price:</em></u>

<u><em /></u>1\ quart\ milk=\$0.76<u><em /></u>

<u><em /></u>

<u><em /></u>Second\ price\ that\ is\ 1\ quart\ milk=\$0.76\ has\ better\ unit\ price<u><em /></u>

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Answer:

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Step-by-step explanation:

4x+7=0

4x=-7+0

4x=-7

x=-7/4

8 0
3 years ago
The perimeter of a rectangle is 48 centimeters. The relationship between the length, the width, and the perimeter of the rectang
scZoUnD [109]

Answer:

The length of the rectangle is 14 cm

Step-by-step explanation:

Here, we want to find the length of the rectangle given the width

Mathematically, the perimeter of the rectangle can be calculated using the formula;

2( l + w)

from the question w = 10

and perimeter = 48

Thus;

2( l + 10) = 48

divide both sides by 2

l + 10 = 48/2

l + 10 = 24

l = 24 - 10

l = 14 cm

8 0
3 years ago
The temperature at sunrise was -3*F. By noon, the temperature climbed 18 degrees. By sundown the temperature was -14*F. How much
Natalija [7]

Answer:

32*F

Step-by-step explanation:

* = degrees

Started at -3*F

By noon, the temperature climbed 18* = +18*

By sundown the temperature was -14*F

What we want to know: How much did the temperature drop between noon and sundown?

This is actually really easy!

What was the temperature at noon?        --> 18*F

What was the temperature at sundown? --> -14*F

So what is the difference between 18* and -14*? We can't use an equation, so we will solve manually.

The distance from -14 to 0 is 14 degrees. Keep that in mind.

The distance from 18 to 0 is 18 degrees. Keep that in mind.

So what is 14 + 18? 14 + 18 = 32*.

So, the temperature dropped 32*F between noon and sundown.

I hope this helps! I know this was a little messy, but that is because we couldn't use an equation/expression to solve this.

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>
6 0
3 years ago
What percent of 68 is 34?<br> Let the unknown number be x.
Sever21 [200]

Answer:

50

Step-by-step explanation:

Lmk if this was the right way to do it or not lol

5 0
3 years ago
1. Determinar la ecuación canónica de la parábola con vértice en (-2,4) y foco en (1,4) 2. Determinar el foco y el vértice de la
goldenfox [79]

Answer:

1. La ecuación de la parábola en forma canónica es x = 1/12 × (y - 4) ² - 2

2. Vértice = (-1, 3), enfoque = (-5/2, 3)

3. y = 12x no es una parábola

4. y = -8x, no es una parábola

Step-by-step explanation:

1. La ecuación estándar de una parábola es y = a · x² + b · x + c

El vértice V es (h, k)

El foco (h + p, k)

Por lo tanto, tenemos en comparación k = 4, h = -2

h + p = 1

p = 1 - h = 1 - (-2) = 3

Lo que da la ecuación como (y - k) ² = 4 · p · (x - h)

Al ingresar los valores de k, h y p, tenemos

(y - 4) ² = 4 × 3 × (x - (-2)) = 12 × (x + 2)

12 · x + 24 = (y - 4) ²

x = 1/12 × (y - 4) ² - 2

La ecuación de la parábola en forma canónica es x = 1/12 × (y - 4) ² - 2

2. Determinar el foco y el vértice de la parábola (y - 3) ² = -6 · (x + 1)

Reescribimos la ecuación en forma de vértice de la siguiente manera;

-6 · x -6 = (y - 3) ²

x = -1 / 6 × (y - 3) ² - 1

La ecuación de una parábola en forma de vértice es x = a · (y - k) ² + h

Con el vértice = (h, k)

Comparando, tenemos, h = -1 yk = 3, el vértice = (-1, 3)

También la ecuación de la parábola en forma cónica es (y - k) ² = 4 · p · (x - h)

Comparando con (y - 3) ² = -6 · (x + 1), tenemos 4p = -6, p = -3/2

El foco está en (h + p, k) que es (-1 + -3/2, 3) = (-5/2, 3)

Vértice = (-1, 3), Enfoque = (-5/2, 3)

3. Para la parábola, y = 12 · x, tenemos;

En comparación con la forma de la ecuación, y = a · x² + b · x + c

b = 12, a = 0, c = 0

Dado que el vértice = (h, k), tenemos;

h = -b / (2 × 0), h = ∞

k = a · h² + b · h + c = ∞

No hay vértice

Foco x valor = Vértice x valor = ∞

No hay foco

Directrix = (k - 1) / (4 · a) = (k - 1) / (4 × 0) = ∞, sin directriz

y = 12x no es una parábola

4. Para y = -8x, tampoco es una parábola como se muestra arriba.

4 0
3 years ago
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