Make use of the inverse sine function. Take the inverse sine of both sides of the equation. Of course, within the appropriate limits, the inverse sine of the sine function is the original argument, as is the case with any inverse function: f⁻¹(f(x)) = x.
... sin⁻¹(sin(x)) = sin⁻¹(-0.5)
... x = sin⁻¹(-0.5)
... x = -30°
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You need to be careful with inverses of trig functions, because they are only defined over a limited domain and range. The range of the inverse sine function is -90° to 90°, so, for example, sin⁻¹(sin(150°)) = sin⁻¹(0.5) = 30°.
5% = 32 therefore 5 * 20 = 100% so 32 * 20 = 640 fuses were inspected
Answer:
B. 5 Hours
Step-by-step explanation:
any work over 40 hours in a 168 hour period is counted as overtime. So take 45 (his total) and subtract it by 40 and you get 5. 45 - 40 = 5 hours.
(3x/2 - 2y a)4
is the answer!