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Dmitrij [34]
3 years ago
9

A 6000-seat theater has tickets for sale at $28 and $40. How many tickets should be sold at each price for a sellout show to gen

erate a total revenue 194400
The number of tickets for sale at $28 should be
The number of tickets for sale at $40 should be​
Mathematics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

3,833 for $28

2167 for $40

Step-by-step explanation:

Let X be the number of tickets sold at the price of $24, And Y be the number of tickets sold at the price of $40.

Now,   $ 28X will be the revenue generated due to the $28 tickets

And,   $40Y will be the revenue generated due to the 40$ tickets.

Now, Total revenue generated should be $194400.

Thus ,   28X + 40Y  = 194400  -(1).

Also,

Total number of seats in theater is 6000.

So, X + Y = 6000.  -(2)

X = 6000 - Y.

Put in equation 1

We get ,    168,000 - 28Y + 40Y = 194,400

                   12Y = 26,000

                      Y = 2,166.66

Since , Y is of 40 $ so minimum tickets sold should be 2167.

X = 3,833.

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