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Reil [10]
3 years ago
8

Factorize using identities:

Mathematics
2 answers:
ivann1987 [24]3 years ago
5 0

Answer: i)169y^3z^3

ii) 225a^3b^3

iii) 145x^2y^2

Step-by-step explanation:

DedPeter [7]3 years ago
4 0
Last part of answer is (9x)^2-(8y)^2

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If log x+y/5 = 1/2(log x + log y) the find the value of x/y + y/x ?​
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Given that

log (x+y)/5 =( 1/2) {log x+logy}

We know that

log a+ log b = log ab

⇛log (x+y)/5 =( 1/2) log(xy)

We know that log a^m = m log a

⇛log (x+y)/5 = log (xy)^1/2

⇛log (x+y)/5 = log√(xy)

⇛(x+y)/5 = √(xy)

On squaring both sides then

⇛{ (x+y)/5}^2 = {√(xy)}^2

⇛(x+y)^2/5^2 = xy

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⇛x^2+y^2+2xy = 25xy

⇛x^2+y^2 = 25xy-2xy

⇛x^2+y^2 = 23xy

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Therefore, (x/y)+(y/x) = 23

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