Answer:
Step-by-step explanation:
Let's solve 2x^2 = -X^2 - 5x - 1. Consolidate all terms on the left side and write 0 on the right side:
3x^2 + 5x + 1 = 0. This is a quadratic equation. Let's solve it for x using the quadratic formula:
a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13. Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.
Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."
Answer C would be correct if and only if we write y = x^2 - 5x - 1.
Answer: The product of (-a + 3)(a + 4) is: -a^2-a+12
Step-by-step explanation:
(-a+3)(a+4) = -a*a-a*4+3*a+3*4
=-a^{2} -4a+3a+12
now just simply combine..
=-a^2-a+12
the answer is -a^2-a+12
Answer:
Step-by-step explanation:
Urn has 3 green and 4 yellow
we choose 2 balls randomly
so samples space for this selection is
![\left [ \left ( Y,G\right ),\left ( G,Y\right ),\left ( G,G\right ),\left ( Y,Y\right )\right ]](https://tex.z-dn.net/?f=%5Cleft%20%5B%20%5Cleft%20%28%20Y%2CG%5Cright%20%29%2C%5Cleft%20%28%20G%2CY%5Cright%20%29%2C%5Cleft%20%28%20G%2CG%5Cright%20%29%2C%5Cleft%20%28%20Y%2CY%5Cright%20%29%5Cright%20%5D)
Event A is choosing differently colored ball form sample space
P(A)=Probability of event (G,Y)+Probability of event (Y,G)
Answer:
Step-by-step explanation:
Coniferous trees keep their needles all year with the exception of tamarack. They are good trees to plant for privacy and wind breaks or shelterbelts
Pines include native white, red, and jack. They have long needles.
Spruces, black and white, and firs. They have short needles. They are important sources of wood fiber in northern Minnesota, and are excellent choices for windbreaks or shelterbelts.
Cedars include white or red. Cedars have scaled needles. Smaller than pines and spruces, cedars can provide wildlife cover and food.
Answer:
Rs 120.
Step-by-step explanation:
10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price
-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2
[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2
0.75[CP+10]=0.85[CP-2]
0.75CP+7.5=0.85CP-1.7
0.85CP-0.75CP=-1.7–7.5=9.2
0.10CP=9.2; CP=9.2/0.10
CP=Rs 92 Cost Price of pen
10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)
From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92
Set CP of Eq 1=CP of Eq 2:
CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;
0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12
0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)
Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.
