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The statement that does not match the others is the one at lower right.
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The barn's volume can be decomposed into a rectangular prism and a triangular one. Thus the <em>upper right</em> expression is a true represenation of the barn's volume:
... Volume of triangular prism + Volume of rectangular prism
The volume of a <em>rectangular prism</em> is the product of its dimensions. The dimensions of the rectangular prism portion of the barn's volume are a, b, c, so the volume of that portion is ...
... Volume of rectangular prism = a·b·c
The volume of a <em>triangular prism</em> is the area of the triangular base multiplied by the length of the prism. Here, the triangular base has base dimension b and height (d-c), so its area is ...
... Area of triangular barn end = (1/2)b(d-c)
Since the length of the barn is "a", the volume of the triangular prism is ...
... Volume of triangular prism = (1/2)b(d-c)a = (1/2)·a·b·(d-c)
The <em>total volume</em> is the sum of the volumes of the parts ...
... a·b·c + (1/2)·a·b·(d-c) . . . . . . matches the <em>upper right</em> selection
This can be factored by removing a·b to outside parentheses:
... a·b·((1/2)·(d-c) + c) . . . . . . . . . matches the <em>lower left</em> selection
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Since the two left selections match the one at upper right, the odd one is the one at lower left.
<u>Given:</u>
The coin wrapper volume = 27,480 mm³.
The coin diameter = 21.18 mm.
There are 50 such coins.
<u>To find:</u>
The thickness (height) of 1 coin.
<u>Solution:</u>
The 50 coins form a cylinder with a volume of 27,480 mm³.
If the diameter is 21.18 mm, the radius of a coin will be mm.
The volume of a cylinder
The volume of all 50 coins is given as 27,480 mm³. We need to determine the height of a single coin.
mm.
So the thickness of 1 coin is 1.5599 mm.