Answer:
optional 6 please
Step-by-step explanation:
my cannot = 1.5
Answer:
The answer is C
Step-by-step explanation:
Just like regular multiplication. Since 8.33 has two spaces after the decimal point, the answer would also have two spaces after the decimal point.
In a quadratic equation
q(x) = ax^2 + bx + c
The discriminant is = b^2 - 4ac
We have that discriminant = 3
If
b^2 - 4ac > 0, then the roots are real.
If
b^2 - 4ac < 0 then the roots are imaginary
<span>In
this problem b^2 - 4ac > 0 3 > 0 </span>
then
the two roots must be real
We can solve
<span>7/9 > x/13
for x.
multiply both sides by 13:
</span>
7/9 > x/13
7/9*13 > x/13 * 3
<span>7/9*13 > x
91/9 > x
reverse it to get
x < 91/9
this says that x has to be less than 91/9 for the inequality </span><span>7/9 > x/13 to be true.
91/9 in decimal form is 10.1 repeating.
the greatest integer x is therefore 10
answer is 10
can verify:
7/9 > x/13
7/9 is approximately 0.777777 so
0.7777 > x / 13
for x = 10, we have 10/13 = 0.7692. and 0.7777 is bigger than that
try next integer. at x = 11, we have 11/13 = 0.8462. this is bigger than 0.7777
so the answer is 10. that's the greatest integer
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