There are 25 identical squares arranged inside the 5 by 5 square matrix. From the drawing it's evident that the length of the side of any one of the smaller squares is just 1. Thus, the perimeter of this one smaller square is P = 4(1), or 4.
The desired perimeter is 4.
Answer:
40 units
Step-by-step explanation:
Given:
Perimeter of ∆ABC = 85 units
AC = 4z
AB = 3z + 3
BC = z + 2
Required:
Numerical value of AC
SOLUTION:
Perimeter of ∆ = sum of all its sides
Perimeter of ∆ABC = AC + AB + BC
85 = 4z + (3z + 3) + (z + 2)
Use this equation to find the value of the variable, z
Collect like terms
Subtract 5 from both sides
Divide both sides by 8
AC = 4z
Plug in the value of x
AC = 4(10)
AC = 40 units
Answer:
x=4
Step-by-step explanation:
2x+3=11
-3 -3
2x=8
2x/2=8/2
x=4
Use S=(n-2)180
S is the sum and N is the number of sides
If you know that the sum is 7560 then plug that in for S
7560=(n-2)180
Then solve for n
7560=180n-360 (note I used distributive property)
7560+360=180n
7920=180n
7920/180=n
n=44 sides
I hope this helps :)
The area for a regular decagon is a bit complicated to type out, but a quick google search "decagon formula" should bring it up.
its like A= (5/2) a^2 sqrt(5+2*sqrt(5)) so yeah just google that and plug the values that they gave you in
i got 1107.97~
the perimeter is P = 10a where a is the side length. in this case it is 12. so the perimeter is 10*(12) which is 120cm.