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lutik1710 [3]
3 years ago
11

Which ordered pair is a solution of the equation? 7x-2y=-57x−2y=−5

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
8 0
Since 7x-2y=-57x−2y=−5
eqn 1 ) 7x-2y=−5
eqn 2) -57x−2y=−5
solve equation 1 for x and plugged into equation 2... x=-5/7+2y/7

-57(-5/7+2y/7)−2y=−5
40.714 -16.286y - 2y =-5
40.714-14.286y = -5

40.714-14.286y = -5
- 40.714 and ÷-14.286 from both sides
y=-3.199

And plug y into equation
x=-5/7+2(3.1999)/7 =0.19997
Stolb23 [73]3 years ago
4 0

Answer:

Neither of the ordered pairs is a solution of the equation.

Step-by-step explanation:

Neither of the ordered pairs is a solution of the equation.

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Step-by-step explanation:

let,A,B be the line which have points (3,-1),(6,7)

here,

(3,-1)=(x1,y1)

(6,7)=(x2,y2)

then,

slope of line AB =(y2-y1/x2-x1)

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=8/3

Now,

equation of the line AB,

(y-y1)=m(x-x1)

(y+1)=8/3(x-3)

3y+3=8x-24

-8x+3y=-24-3

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8x-3y=27

Hence, the equation of the line through the points (3,-1) ,(6,7) is 8x-3y=27.

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Step-by-step explanation:

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8 0
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\dfrac{-2}{3} \div 2\dfrac{1}{4} = <br> 3<br> −2<br> ​ <br> ÷2 <br> 4<br> 1<br> ​
bekas [8.4K]

Answer:

\dfrac{-2}{3} \div 2\dfrac{1}{4} = \dfrac{-8}{27}

Step-by-step explanation:

Given

\dfrac{-2}{3} \div 2\dfrac{1}{4} =

Required

Solve

Start by converting the mixed number to improper fraction

\dfrac{-2}{3} \div \dfrac{9}{4} =

Convert the division to muliplication

\dfrac{-2}{3} * \dfrac{4}{9} =

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Hence:

\dfrac{-2}{3} \div 2\dfrac{1}{4} = \dfrac{-8}{27}

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Answer:

Step-by-step explanation:

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