Question

Recall that DNA and RNA are synthesized only in the 5'→3' direction and that DNA and RNA sequences are written in the 5'→3' direction, unless otherwise noted.
Consider the following DNA sequence:
5' TTGAAATGCCCGTTTGGAGATCGGGTTACAGCTAGTCAAAG 3'
3' AACTTTACGGGCAAACCTCTAGCCCAATGTCGATCAGTTTC 5'

Part A) Identify bases in the bottom strand that can be transcribed into start and stop codons. Write the mRNA sequence (in the form of triplets, for example, GGG-AAA-CCC) that would be transcribed between start and stop codons if the bottom strand served as the template for RNA polymerase.

Part B) Write the amino acid sequence that would be translated from the mRNA sequence you just wrote.

Enter your answer using 3-letter abbreviations for amino acids as in the example: Val-Arg-Ser-Trp

Answer 1

Answer:

The Transcription mRNA

5'- AUG-CCC-GUU-UGG-AGA-UCG-GGU-UAC-AGC-UAG-3'

The translation product

5' Met-Pro-Val-Trp-Arg-Ser-Gly-Tyr-Ser-3'

Explanation:

Transcription is a process which transcripts the DNA to a molecule called mRNA or messenger RNA which contains code for the synthesis of amino acids.

The RNA nucleotide base pairs are added in the same way as in the DNA that is guanine will bind cytosine but adenine will bind uracil instead of thymine.

Since the start codon is AUG which codes for methionine and stop codons could be UAG, UAA or UGA which do not code for the amino acids during translation.

In the given question,  

Looking for the start codon which is AUG in the template strand is found and the transcript mRNA thus will be coded as

Template strand

3' AACTT-TACGGGCAAACCTCTAGCCCAATGTCGATCAGTTTC 5'

The Transcription mRNA

5'- AUG-CCC-GUU-UGG-AGA-UCG-GGU-UAC-AGC-UAG-3'

The translation product

5' Met-Pro-Val-Trp-Arg-Ser-Gly-Tyr-Ser-3'