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GrogVix [38]
4 years ago
9

HELP ASAP PLEASE!!!

Mathematics
1 answer:
lina2011 [118]4 years ago
8 0

Answer:

C

y = x² - 4x - 5


Step-by-step explanation:

looking at the graph it crosses the x axis at 5 and -1

using the zero product property in reverse we can find the equation

subtract the roots from x and set equal to zero

(x-a) (x-b) =0  where a and b are the roots of the quadratic

(x-5) (x--1) = 0

(x-5) (x+1) =0

Foil

first x*x=x^2

outer : x*1=1x

inner: -5*x=-5x

last : -5*1=-5

add these together

x^2 +x-5x-5=0

x^2 -4x-5 =0

now set this equal to y to find points outside the x axis

y = x^2 -4x-5

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Find the GCF <br><br> <img src="https://tex.z-dn.net/?f=32xy-18%20x%5E%7B2%7D%20" id="TexFormula1" title="32xy-18 x^{2} " alt="3
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