Answer:
100
Step-by-step explanation:
Answer:
3.45652173913
Step-by-step explanation:
the equation is 159 divided by 46
Answer:
- x ≥ 2009
- 3.2x -6222.8
- 257.2 mm
- year 2100
Step-by-step explanation:
1. The problem statement tells you the function applies for year values (x) 2009 and later. The domain is real numbers greater than or equal to 2009.
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2. We can use the distributive property to eliminate parentheses:
3.2(x -2009) +206 = 3.2x -6428.8 +206
= 3.2x -6222.8
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3. Put 2025 in the equation and do the arithmetic
g(2025) = 3.2·2025 -6222.8 = 257.2 . . . . mm
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4. Put this value of level rise in the equation and solve for x.
g(x) = 3.2x -6222.8
500 = 3.2x -6222.8 . . put 500 mm where g(x) is in the equation
6722.8 = 3.2x . . . . . . . add 6222.8
x = 6722.8/3.2 = 2100.875
The water rise will be equal to about half a meter late in the year 2100.
Answer:
<em>The freezing point of water increases by 0.0001 degrees Fahrenheit when the altitude increases by 1 foot.</em>
Step-by-step explanation:
The model for the freezing point of water T at altitude a is:
T(a)= 0.0001a+32
The slope of this equation is the coefficient of the variable a. Since the slope is positive, it means the freezing point of water increases by 0.0001 degrees Fahrenheit when the altitude increases by 1 foot.
For example, when a=1000, the freezing point is:
T(1000)= 0.0001*1000+32 = 32.1°F
When a=1001, the freezing point is:
T(1001)= 0.0001*1001+32 = 32.1001°F
Note the increase of 1 foot in altitued meant an increase of 32.1001-32.1 = 0.0001°F
