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anastassius [24]
4 years ago
9

what is a 5 digit number that when rounded to the nearest thousand and hundred will have the same result

Mathematics
1 answer:
vaieri [72.5K]4 years ago
7 0
No it will not be the same results
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Consider the following two quantities:
inessss [21]

The slope of the line is -2.5 and the y-intercept is 2. This shows that the Quantity B is greater that A

<h3>How to find the intercept of a line</h3>

The intercept is the point where the line intersects

Determine the slope of the graph using the coordinate points (0, 2) and (0.8, 0)
Slope = -2/0.8
Slope = -2.5

The slope of the line is -2.5 and the y-intercept is 2

This shows that the Quantity B is greater than A

Learn more on equation of a line here:brainly.com/question/13763238

6 0
2 years ago
3(2x+x)/6 &gt; 1/3x+2 solve for x
tangare [24]

1)Find all the like terms=3x3x/6>1/3x+2

2)Multiply both sides by six=9x>2x+12

3)Move the variables to the left side and change the sign=9x-2x>12

4)Find the like terms=7x>12

5)Divide by sides by seven=x>12/7

6)Your answer is x>12/7

I hope this helps! :)

4 0
3 years ago
A piece of wood is to be cut so that it is square and has an area of 45 square inches. how long should the sides be, rounded to
Y_Kistochka [10]
6.70 inches is the rounded answer

3 0
4 years ago
A new, trendy department store is experiencing exponential growth across America. The chain began in 2004 when it opened 16 stor
QveST [7]
The equation is y=16(1.35)ˣ.

This equation is of the form y=a(1+r)ˣ, where a is the initial amount, r is the rate of growth expressed as a decimal number, y is the total, and x is the amount of time.  For our problem, a is 16; b is 0.35 (35%=35/100=0.35).  This gives us the equation above.
7 0
3 years ago
Dy/dx = 2xy^2 and y(-1) = 2 find y(2)
Anarel [89]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2887301

—————

Solve the initial value problem:

   dy
———  =  2xy²,      y = 2,  when x = – 1.
   dx


Separate the variables in the equation above:

\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\&#10;\mathsf{y^{-2}\,dy=2x\,dx}


Integrate both sides:

\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\&#10;\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\&#10;\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\&#10;\mathsf{-\,\dfrac{1}{y}=x^2+C_1}

\mathsf{\dfrac{1}{y}=-(x^2+C_1)}


Take the reciprocal of both sides, and then you have

\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}


In order to find the value of  C₁  , just plug in the equation above those known values for  x  and  y, then solve it for  C₁:

y = 2,  when  x = – 1. So,

\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\&#10;\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\&#10;\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\&#10;\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\&#10;\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}

\mathsf{C_1=-\,\dfrac{3}{2}}


Substitute that for  C₁  into (i), and you have

\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\&#10;\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\&#10;\mathsf{y=-\,\dfrac{2}{2x^2-3}}


So  y(– 2)  is

\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\&#10;\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\&#10;\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\&#10;\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)


Tags:  <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0
4 years ago
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