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Anastaziya [24]
4 years ago
12

What does the R in the acronym SMART stand for??

Computers and Technology
1 answer:
jeyben [28]4 years ago
7 0
Depending on who you ask, it is either Realistic or Relevant. Organizations that can't choose sometimes use the acronym SMARRT.
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Write a SELECT statement that returns one row for each customer that has orders with these columns: The email_address from the C
bazaltina [42]

Answer:

Please find the attachment files of the queries:

Explanation:

In the all queries the select statement is used that selects the defined columns and use the function like sum, join, orderby, and groupby to perform the various operations, in which the sum is used to add columns or rows values, join is used for joining two or more tables, and orderby is used for return the table into ascending or descending order, and groupby is used for the count the value, calculate average and perform other operation and gives its return value.

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For security reasons, the network administrator needs to prevent pings into the corporate networks from hosts outside the intern
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ICMP

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Which are the benefits of leveraging web technologies?
allsm [11]

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Free point giveaway pt.10 and brainliest to first answer
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Computer A has an overall CPI of 1.3 and can be run at a clock rate of 600 MHz. Computer B has a CPI of 2.5 and can be run at a
kirill115 [55]

Answer:

Check the explanation

Explanation:

CPI means Clock cycle per Instruction

given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M

Execution time is given by following Formula.

Execution Time(CPU time) = CPI*Instruction Count * clock time = \frac{CPI*Instruction Count}{ClockRate}

a)

for system A CPU time is 1.3 * 100, 000 600 106

= 216.67 micro sec.

b)

for system B CPU time is =\frac{2.5*100,000}{750*10^6}

= 333.33 micro sec

c) Since the system B is slower than system A, So the system A executes the given program in less time

Hence take CPU execution time of system B as CPU time of System A.

therefore

216.67 micro = =\frac{2.5*Instruction}{750*10^6}

Instructions = 216.67*750/2.5

= 65001

hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A

3 0
3 years ago
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