The rule is that: You are adding 5 each time
5(100) + 4 = 504
Your answer should be 504
hope this helps
The length is 13 and the width is 6. The way I figured it out is: find two factors of the area (that if multiplied with each other, they equal the area) and see which ones add up and then get multiplied by two to find the perimeter. I found 6 and 13 and then added them together to get 19. Then I multiplied 19 by two and got 38. This is how I have always done it idk.
Your answer is length = 13 and width = 6.
hope this helps :)
Step-by-step explanation:
The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:
let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9
let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9
let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9
let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9
let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9
let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9
You can continue to increase the length of the square and follow this pattern and it will be consistent.
