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Mama L [17]
3 years ago
5

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Softa [21]3 years ago
8 0
180^o-112^o=68^o

\left\{\begin{array}{ccc}2x+3y=68&|\cdot(-15)\\30x+11y=112\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-30x-45y=-1020\\30x+11y=112\end{array}\right}\\.\ \ \ \ \ \ \ -34y=-908\ \ \ |:(-34)\\\\.\ \ \ \ \ \ \ \ \ \ \  y=\dfrac{908}{34}\to y=\dfrac{454}{17}\\\\2x+3\cdot\dfrac{454}{17}=68\ \ \ \ |\cdot17\\\\34x+1362=1156\ \ \ \ |-1362\\34x=-206\ \ \ \ |:34\\\\x=-\dfrac{206}{34}\to x=-\dfrac{103}{17}\\\\  \left\{\begin{array}{ccc}x=-\dfrac{103}{17}\\\\y=\dfrac{454}{17}\end{array}\right
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The slope for (0,7) and (7,7)
Softa [21]

Answer:

slope = 0

Step-by-step explanation:

point1 =  (0,7)

point 2 =(7,7)

slope = (y2-y1)/(x2-x1) => (7-7)/(7-0)

slope = 0

4 0
2 years ago
Read 2 more answers
For each point identify the axis or quadrant where the point is located…
My name is Ann [436]

Answer:

quadrant ll

Step-by-step explanation:

A point on the y-axis will always have an x-coordinate of zero. Instructions: In the figure above, the point with coordinates (4,2) is located in quadrant I. The point with coordinates (-3,4) is located in quadrant II.

6 0
3 years ago
Hello need help please with Divide rational and simplify
aliina [53]
Dividing fractions is the same as multiplying by its reciprocal so you can change the equation to this
\frac{ - 14 + 7x}{4}  \times  \frac{4}{4 - 2x}
And you can simplify by eliminating the fours and multiplying straight across
\frac{ - 14 + 7x}{4 - 2x}
You can pull out - 7 from the top and 2 from the bottom so you have this
\frac{ - 7(2  -  x)}{2(2 - x)}
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5 0
2 years ago
Let m=4 and n=36. What is the value of m+.9?​
Anna11 [10]
Answer:
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Explanation:
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Replace m with the given value:
4 + .9

Add them together:
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3 0
2 years ago
Find the vertex of the graph of f(x)=-4(x-1)(x+5)
madreJ [45]

The vertex of the graph is (h, k) = (- 2, 36).

<h3>How to find analytically the vertex of a quadratic equation</h3>

In this question we have a quadratic equation of the form f(x) = a · (x - r₁) · (x - r₂) and we need to transform the expression into its vertex form of determine the coordinates of the vertex. First, we need to exprand the expression:

f(x) = - 4  · (x - 1) · (x + 5)

f(x) = - 4 · (x² + 4 · x - 5)

f(x) = - 4 · x² - 16 · x + 20

Now we proceed to complete the square:

f(x) = - (4 · x² + 16 · x - 20)

- f(x) = 4 · x² + 16 · x - 20

- f(x) = (2 · x)² + 8 · (2 · x) - 20

- f(x) + 36 = (2 · x)² + 8 · (2 · x) + 16

- f(x) + 36 = (2 · x + 4)²

- f(x) + 36 = 4 · (x + 2)²

f(x) - 36 = - 4 · (x + 2)²

The vertex of the graph is (h, k) = (- 2, 36).

To learn more on quadratic equations: brainly.com/question/17177510

#SPJ1

7 0
1 year ago
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