Answer:
20 cm
Step-by-step explanation:
Given that :
P = 1/25 r²h
P = price = 240 ; h = height = 15cm
Inputting values into the equation :
240 = 1/25 * r² * 15
25 * 240 = 15r²
6000 = 15r²
6000 / 15 = r²
400 = r²
Square root of both sides
20 = r
Radius = 20cm
Answer:
Step-by-step explanation:
2X+4)+(2X+4)+X+X=38
Lets add our X's and then add our whole numbers. 6X+8=38
Lets work our sentence by subtracting 8 from each side of the equal sign.
6X+8–8=38–8
6X=30
Lets divide each side by 6.
6X/6=30/6
X=5 now lets prove 5 is X.
(2×5+4)+(2×5+4)+5+5=38
(14)+(14)+5+5=38
28+10=38
38=38
X is equal to 5.
Answer:
I think its like a cartoon or something like that
https://hbomax-images.warnermediacdn.com/images/GXyniGAhmEcJZOgEAAABz/tileburnedin?size=1280x720&format=jpeg&partner=hbomaxcom&productCode=hbomax&host=artist.api.cdn.hbo.com&w=1200
there image I think
Answer:
Part 1) ![AC=6\sqrt{3}\ units](https://tex.z-dn.net/?f=AC%3D6%5Csqrt%7B3%7D%5C%20units)
Part 2) ![AC=12\sqrt{3}\ units](https://tex.z-dn.net/?f=AC%3D12%5Csqrt%7B3%7D%5C%20units)
Step-by-step explanation:
I will analyze two problems
see the attached figure to better understand the problem
Problem 1
The hypotenuse is the segment AB and the right angle is C
we know that
In the right triangle ABC
---> by SOH (opposite side divided by the hypotenuse)
substitute the given values
![sin(60^o)=\frac{AC}{12}](https://tex.z-dn.net/?f=sin%2860%5Eo%29%3D%5Cfrac%7BAC%7D%7B12%7D)
Remember that
![sin(60^o)=\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=sin%2860%5Eo%29%3D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
substitute
![\frac{\sqrt{3}}{2}=\frac{AC}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%3D%5Cfrac%7BAC%7D%7B12%7D)
![AC=6\sqrt{3}\ units](https://tex.z-dn.net/?f=AC%3D6%5Csqrt%7B3%7D%5C%20units)
Problem 2
The hypotenuse is the segment BC and the right angle is A
we know that
In the right triangle ABC
---> by TOA (opposite side divided by the adjacent side)
substitute the given values
![tan(60^o)=\frac{AC}{12}](https://tex.z-dn.net/?f=tan%2860%5Eo%29%3D%5Cfrac%7BAC%7D%7B12%7D)
Remember that
![tan(60^o)=\sqrt{3}](https://tex.z-dn.net/?f=tan%2860%5Eo%29%3D%5Csqrt%7B3%7D)
substitute
![\sqrt{3}=\frac{AC}{12}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%3D%5Cfrac%7BAC%7D%7B12%7D)
![AC=12\sqrt{3}\ units](https://tex.z-dn.net/?f=AC%3D12%5Csqrt%7B3%7D%5C%20units)