Solve the system of equations. 13x−y=90

A cup manufacturing company makes small and large snow cone cups with the dimensions shown in the diagram. Which statement

hoa [83]

C) The volume of the large cone is 3 times the volume of the small cone.

Step-by-step explanation:

Step 1:

The volume of a cone is determined by multiplying $\frac{1}{3}$ with π, the square of the radius (r²) and height (h). Here we substitute π as 3.1415.

The radius of the large cone is 1.5 inches and the height is 4 inches.

The volume of the larger cone $= \frac{\pi r^{2} h}{3} = \frac{(3.1415)(1.5^{2} )(4)}{3} = \frac{28.2735}{3} = 9.4245.$

So the volume of the larger cone is 9.4245 cubic inches.

Step 2:

Now, we determine the volume of the small cone.

The radius of the small cone is 1 inch and the height is 3 inches.

The volume of the small cone $= \frac{\pi r^{2} h}{3} = \frac{(3.1415)(1^{2} )(3)}{3} = \frac{9.4245}{3} = 3.1415.$

So the volume of the smaller cone is 3.1415 cubic inches.

Step 3:

Now we divide the values on the volume of the large cone by the volume of the small cone.

The volume of the large cone by the volume of the small cone $= \frac{9.4245}{3.1415} = 3.$

So the volume of the large cone is 3 times the volume of the small cone which is option C.

8 0

4 years ago

What is the area of a polygone with vertices (-3,4) (2,4) (4,2) (2,-3) and (-3,-3)

sweet [91]

By summing the areas of minor rectangles and triangles, the area of the irregular polygon whose vertices are (- 3, 4), (2, 4), (4, 2), (2, - 3) and (- 3, - 3) is equal to 42 square units.

<h3>How to determine the area of a irregular polygon</h3>

In this problem we have to determine the area of a irregular polygon, whose calculation is defined as a sum of the areas of triangles and rectangles. To determine the combination of squares and triangles, we need first to plot the vertices and construct the figure on a Cartesian plane.

The area of the irregular figure is:

A = (5) · (7) + 0.5 · 2² + 0.5 · (2) · (5)

A = 35 + 2 + 5

A = 42

By summing the areas of minor rectangles and triangles, the area of the irregular polygon whose vertices are (- 3, 4), (2, 4), (4, 2), (2, - 3) and (- 3, - 3) is equal to 42 square units.

To know more on polygons: brainly.com/question/10441863

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