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Sati [7]
3 years ago
10

Numbers 20 - 22 please

Mathematics
1 answer:
Deffense [45]3 years ago
5 0
(x+5)(x+2)=x^2+2x+5x+10=x^2+7x+10\\\\
(x-1)(2x^2-4x+10)=2x^3-4x^2+10x-2x^2+4x-10=\\
=2x^3-6x^2+14x-10\\\\
(c^2-10)(4c+3)=4x^3+3c^2-40c-30

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If g(x) is a linear function such that g(-3) = 2 and g(1) = -4, find g(7).
eimsori [14]
<h3>Answer:   -13</h3>

=======================================

Explanation:

g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)

g(1) = -4 means we have the point (1,-4)

Find the slope of the line through the two points (-3,2) and (1,-4)

m = (y2-y1)/(x2-x1)

m = (-4-2)/(1-(-3))

m = (-4-2)/(1+3)

m = -6/4

m = -3/2

m = -1.5

The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5

Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation:  2 = -1.5*(-3) + b

Let's solve for b

2 = -1.5*(-3)+b

2 = 4.5 + b

2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides

-2.5 = b

b = -2.5

Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5

The last step is to plug in x = 7 and compute

g(x) = -1.5*x - 2.5

g(7) = -1.5*7 - 2.5

g(7) = -10.5 - 2.5

g(7) = -13

6 0
3 years ago
Read 2 more answers
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