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Sati [7]
3 years ago
10

Numbers 20 - 22 please

Mathematics
1 answer:
Deffense [45]3 years ago
5 0
(x+5)(x+2)=x^2+2x+5x+10=x^2+7x+10\\\\
(x-1)(2x^2-4x+10)=2x^3-4x^2+10x-2x^2+4x-10=\\
=2x^3-6x^2+14x-10\\\\
(c^2-10)(4c+3)=4x^3+3c^2-40c-30

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Answer:

1) Se siembra cinco doceavas partes del terreno con claveles rojos y amarillos, 2) Se siembra siete doceavas partes del terreno con claveles blancos.

Step-by-step explanation:

El enunciado se encuentra incompleto. La pregunta faltante es:

2 ¿Qué parte del terreno corresponde a los claveles blancos?

1) Sea A el área total sembrada con los tres tipos de claveles. Entonces, las áreas sembradas con claveles rojos y claveles amarillos son \frac{1}{6}\cdot A y \frac{1}{4} \cdot A, respectivamente.

El área sembrada con claveles rojos y amarillos se obtiene al sumar las áreas correspondientes, es decir:

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x = \left(\frac{1}{6}+\frac{1}{4}\right)\cdot A

x = \left(\frac{4+6}{24} \right)\cdot A

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2) El área sembrada con claveles blancos se obtiene al sustraer el área obtenida en el punto anterior del área total. Esto es:

x = A - \frac{5}{12}\cdot A

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x = \frac{7}{12}\cdot A

Se siembra siete doceavas partes del terreno con claveles blancos.

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