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Sati [7]
3 years ago
10

Numbers 20 - 22 please

Mathematics
1 answer:
Deffense [45]3 years ago
5 0
(x+5)(x+2)=x^2+2x+5x+10=x^2+7x+10\\\\
(x-1)(2x^2-4x+10)=2x^3-4x^2+10x-2x^2+4x-10=\\
=2x^3-6x^2+14x-10\\\\
(c^2-10)(4c+3)=4x^3+3c^2-40c-30

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Answer:

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Step-by-step explanation:

Recall the formula to transform radians to degrees and vice-versa:

\angle\,radians=\frac{\pi}{180^o} \,* \,\angle degrees\\  \\\angle\,degrees=\frac{180^o}{\pi} \,* \,\angle radians

Therefore we can investigate each of the statements, and find that when we have a \frac{\pi}{6}  radians angle, then its degree formula becomes:

\angle\,degrees=\frac{180^o}{\pi} \,* \,\angle radians\\\angle\,degrees=\frac{180^o}{\pi} \,* \,\frac{\pi}{6} \\\angle\,degrees=\frac{180^o}{6} \\\angle\,degrees=30^o

also when an angle measures 180^o  , its radian measure is:

\angle\,radians=\frac{\pi}{180^o} \,* \,\angle degrees\\\angle\,radians=\frac{\pi}{180^o} \,* \,180^o\\\angle\,radians=\pi

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