Some students were asked what kinds of animals they have at home.
1 answer:
(a) Animals by popularity; Dogs, Cats, Others, Horses.
(b) If 250 students were interviewed, 20 students have other pets.
(c) No, it was incorrect.
Step-by-step explanation:
Step 1; We arrange the different pets in chronological order, from the highest percent to the lowest percent;
1. Dogs - 67%,
2. Cats - 20%
3. Others - 8%,
4. Horses - 1%.
None is not included in this list.
Step 2; If 250 students were interviewed, 8% of those have other pets. So we need to calculate how much 8% of 250 is.
8% of 250 = × 250 = 0.08 × 250 = 20.
So 20 students had other pets.
Step 3; 20% of the interviewed students had cats. If 75 students had cats, we need to equate 20% to the 75 and find out how many students were actually interviewed.
20% × x = 75, 0.2 × x = 75,
x = = 375.
So if 375 students were interviewed, 75 students would have cats. So the estimate of 250 students being interviewed is incorrect.
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First, let's use the given information to determine the function's amplitude, midline, and period.
Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.
Finally, we should determine the parameters of the function's formula by considering all the above.
Determining the amplitude, midline, and period
The midline intersection is at y=5 so this is the midline.
The maximum point is 1 unit above the midline, so the amplitude is 1.
The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
Determining the type of function to use
Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function.
This means there's no horizontal shift, so the function is of the form -
a sin(bx)+d
Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.
The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1.
The midline is y=5, so d=5.
The period is 4π so b = 2π / 4π = 1/2 simplified.
<span>= Solution </span>
Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.
Finally, we should determine the parameters of the function's formula by considering all the above.
Determining the amplitude, midline, and period
The midline intersection is at y=5 so this is the midline.
The maximum point is 1 unit above the midline, so the amplitude is 1.
The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
Determining the type of function to use
Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function.
This means there's no horizontal shift, so the function is of the form -
a sin(bx)+d
Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.
The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1.
The midline is y=5, so d=5.
The period is 4π so b = 2π / 4π = 1/2 simplified.
Answer:the attached file shows the solution
