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Bezzdna [24]
4 years ago
15

What "i" can be simplified to -1

Mathematics
2 answers:
mel-nik [20]4 years ago
8 0
When "i" is raised to a power divisible by 4, it can be simplified to 1 (i^4, i^64, etc.)
When "i" is raised to a power divisible by 3, it can be simplified to -i (i^3, i^27, etc.)
When "i" is raised to a power divisible by 2 but not 4, it can be simplified to -1 (i^2, i^10, etc.)
When none of this is true for the power "i" is being raised to, then it can be simplified to "i" (i^5, i^11, etc.)
Rudiy274 years ago
3 0
I=√-1
i²=(√-1)²=-1


the answer is i²
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Please show work and help me pls
Gekata [30.6K]

Answer:

The answer is 207.

Step-by-step explanation:

If you do 1 ÷ 3 you'd get 3. Then move on too the 1 in 3105. 1 ÷ 1 equals 1. You do that with the 0 and the 5 in 3105. The last step too do is is do the same thing with the 5 in 15. Such as, 5 ÷ 3, 5 ÷ 1, 5 ÷ 0, and lastly 5 ÷ 5. Now if you understand just divide the two numbers in 15, which are 1 and 5 to get the quotient in the division problem. Hope this helps, I'm not the greatest at explaining!

7 0
3 years ago
Members of a baseball team raised $1780.50 to go to a tournament. They rented a
Alina [70]

Answer: 17 players

Step-by-step explanation: 1780.50-1151.50=629, 629/37 = 17

3 0
2 years ago
What is the value of cosine theta in the diagram below?<br> a) 3/5<br> b) 3/4<br> c) 4/5<br> d) 4/3
anzhelika [568]

Answer:

cos(x)=0.6

Step-by-step explanation:

cos(x) represents the horizontal distance of the unit vector

sin(x) represents the vertical distance of the unit vector (0.8)

tan(x) represents the distance on the tangent line from the point to the x-axis

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4 0
3 years ago
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Savatey [412]
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3 years ago
15 trucks can carry 26,850 kg weight. Find the weight carried by one truck.
nadya68 [22]

\huge\underline{\underline{\boxed{\color{blueviolet}{ANSWER}}}}

★ 15 trucks can carry 26,850 kg weight

★ We've to find the weight carried by one truck

\huge \pink {\overline{ \quad \quad \quad \quad \quad \quad \quad\quad \quad}}

\sf{Number  \: of \:  trucks = 15 }

\sf{Weight  \: carried  \: by  \: one \:  truck = \frac{26,850Kg}{15} }

\sf  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:                  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:= 1790Kg

Therefore , the weight carried by one truck is 1790 kg

7 0
2 years ago
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