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3 years ago

1 7/10 x 2/3 what is the product

Mathematics

1 answer:

Ludmilka [50]3 years ago

7 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{1 \frac{2}{15}}}}}}$

Step-by-step explanation:

$\sf{1 \frac{7}{10} \times \frac{2}{3} }$

Convert the mixed number into improper fraction

$\longrightarrow{ \sf{ \frac{10 \times 1 + 7}{10} \times \frac{2}{3}}}$

$\longrightarrow{ \sf{ \frac{17}{10} \times \frac{2}{3}}}$

To multiply one fraction by another, multiply the numerators for the numerator, and multiply the denominator for its denominator and reduce the fraction obtained after multiplication into lowest term

$\longrightarrow{ \sf{ \frac{17 \times 2}{10 \times 3}}}$

$\longrightarrow{ \sf{ \frac{34}{30}}}$

$\longrightarrow{ \sf{ \frac{17}{15} }}$

Convert the improper fraction into mixed number

$\longrightarrow{ \sf{1 \frac{2}{15} }}$

Hope I helped!

Best regards! :D

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Brianna has x nickels and y pennies. She has no less than 20 coins worth no more

Bond [772]

Answer:

$y \ge 20 - x$

$y \le 80 -5x$

$(x,y) = (15,5)$

Step-by-step explanation:

Given

$Nickels = x$

$Pennies = y$

$Amount = \$0.80$ maximum

$Coins = 20$ minimum

Required

Solve graphically

First, we need to determine the inequalities of the system.

For number of coins, we have:

$x\ +\ y\ge 20$ because the number of coins is not less than 20

For the worth of coins, we have:

$0.05x\ +\ 0.01y\ \le0.80$ because the worth of coins is not more than 0.80

So, we have the following equations:

$x\ +\ y\ge 20$

$0.05x\ +\ 0.01y\ \le0.80$

Make y the subject in both cases:

$y \ge 20 - x$

$0.01y \le 0.80 - 0.05x$

Divide through by 0.01

$\frac{0.01y}{0.01} \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}$

$y \le \frac{0.80}{0.01} -\frac{ 0.05x}{0.01}$

$y \le 80 -5x$

The resulting inequalities are:

$y \ge 20 - x$

$y \le 80 -5x$

The two inequalities are plotted on the graph as shown in the attachment.

$y \ge 20 - x$ --- Blue

$y \ge 80 -5x$ --- Green

Point A on the attachment are possible solutions

At A:

$(x,y) = (15,5)$

4 0

2 years ago

I need help on 3,4 and 5!!!Please!!!

gayaneshka [121]

Well, for 4 I believe you must divide 2/4 by 100 to make it a decimal, then divide the decimal by the 5. :) Hopefully that is correct!

4 0

2 years ago

Read 2 more answers

Can someone pls help??

Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b. The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 = 81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1 or -10 = -y1

Multiply by -1

-14 = y1 or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 = 144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1 or -7 = -y1

Multiply by -1

-11 = y1 or 7 = y1

The y coordinates for A are either -11 or 7

3 0

3 years ago

What are the factors of 21

sweet-ann [11.9K]

Answer:

21: 3and 7 factors

54: 6and 9 factors

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2 years ago

Isaac surveyed the employees at a law firm. Each employee was asked to record their highest level of education completed. The re

Len [333]

Answer: 65 people completed graduate school.

Step-by-step explanation:

25% of 260 is 65.

6 0

2 years ago

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