What is the perimeter of a polygon with vertices at (3, 2) , (3, 9) , (7, 12) , (11, 9) , and (11, 2) ?
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Answer:
not factorable
Step-by-step explanation:
The easiest way to factor is to find two numbers of the "a" value (the coefficient before ) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:
1 -10 --> 1(-10) gives you -10
1 -1 --> 1(-1) gives you -1
adding these together -10 + (-1) = -11 which does not equal -9.
You could stop here and conclude that this is not factorable by inspection.
Another method: using the quadratic formula to find its roots.
Roots: and