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ehidna [41]
3 years ago
11

What is 9 to the 4th power * 9 to the negative 4th power ​

Mathematics
2 answers:
Elena-2011 [213]3 years ago
8 0

9 to the 4th power is 6561

Tema [17]3 years ago
7 0

(9^4)/(9^-4)= 43046721

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Which description explains how the graph of f(x)=√x could be transformed to form the graph of g(x) = √x-6
yawa3891 [41]

Answer:

b

c

Step-by-step explanation:

First question: x - 6 means there is a shift to the right.

Second Question: substitute the given values into the original equation for appropriate transformations.

Answer: 3 |x-4| + 2, because vertical stretch multiplies x, horizontal shifts are subtracted or added to x, and vertical shifts are added or subtracted to the entire function.

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3 years ago
Which of the following is the equation of a horizontal line
ICE Princess25 [194]
The point (a,b) is (5,7) . Therefore, the equation of the line is y=7
4 0
3 years ago
Two consecutive whole numbers are n-1 and n
Orlov [11]

a. n-(n - 1) = 1

b. n( n - 1) = n² - n

c. (n - 1) + n = 2n - 1

d. (n - 1) + n = 2n - 1

<h3>Solution:</h3>

General Rule for Equation Solving

  • Remove parentheses and combine like terms to simplify each side of the equation.
  • To isolate the variable term on one side of the equation, use addition or subtraction.
  • To find the variable, use multiplication or division.

Given two consecutive numbers , (n - 1) , n

simplifying :

n - (n - 1)

= n -1(n - 1)

= n - n + 1

= 1

multiplying :

n( n -1)

= n² - n

simplifying :

(n-1) + n

= n - 1 + n

= 2n -1

by adding two numbers :

(n - 1) + n

= n -1 + n

= 2n - 1

To learn more about equations refer to :

brainly.com/question/22688504

#SPJ13

5 0
9 months ago
The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.
Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

h(t)=-16t^2+80t+64

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A)  Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

so

For h(t)=0

-16t^2+80t+64=0

Solve the quadratic equation

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^2+80t+64=0

so

a=-16\\b=80\\c=64

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}

t=\frac{-80\pm\sqrt{10,496}} {-32}

t=\frac{-80+\sqrt{10,496}} {-32}=-0.70

t=\frac{-80-\sqrt{10,496}} {-32}=5.70

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

-16t^2+80t+64=40

-16t^2+80t+24=0

Solve the quadratic equation

we have

a=-16\\b=80\\c=24

substitute in the formula

t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}

t=\frac{-80\pm\sqrt{7,936}} {-32}

t=\frac{-80+\sqrt{7,936}} {-32}=-0.28

t=\frac{-80-\sqrt{7,936}} {-32}=5.28

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0
3 years ago
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