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AnnyKZ [126]
2 years ago
6

You have been asked to build a scale model of a restaurant out of bottle caps. The restaurant is 20 feet tall. Your scale is 2.4

cm: 1 foot. A bottle cap is 1.2 cm tall. About how many bottle caps tall will your model be?
Mathematics
1 answer:
Amanda [17]2 years ago
8 0

Answer:

40\ bottle\ caps

Step-by-step explanation:

we know that

The scale is \frac{2.4}{1}\ \frac{cm}{ft}

That means

2.4 cm in the model represent 1 foot in the real

In this problem

The restaurant is 20 feet tall

Find the height of the model

Multiply the actual height of the restaurant by the scale 2.4

20\ ft=20(2.4)=48\ cm

A bottle cap is 1.2 cm tall

To find out the number of bottle caps divide the height of the model by 1.2

\frac{48}{1.2}= 40\ bottle\ caps

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I need help with #47 to #50 ASAP…. Please help me with it
Ksenya-84 [330]

Step-by-step explanation:

a triangular number n is the sum of all natural numbers <= n.

t1 = 1

t2 = 1+2 = 3

t3 = 1+2+3 = 6

t4 = 1+2+3+4 = 10

...

so,

tn = tn-1 + n

47.

1×8 + 1 = 9 is a square number.

3×8 + 1 = 25 is a square number

6×8 + 1 = 49 is a square number

10×8 + 1 = 81 is a square number

48.

1/3 = 0 remainder 1

3/3 = 1 remainder 0

6/3 = 2 remainder 0

10/3 = 3 remainder 1

15/3 = 5 remainder 0

21/3 = 7 remainder 0

28/3 = 9 remainder 1

so, there seems to be a pattern 1 0 0 1 0 0 1 0 0 1 ...

49.

1/4 = 0 remainder 1

4/4 = 1 remainder 0

9/4 = 2 remainder 1

16/4 = 4 remainder 0

25/4 = 6 remainder 1

36/4 = 9 remainder 0

49/4 = 12 remainder 1

so, there seems to be a pattern 1 0 1 0 1 0 1 0 1 0 1 ...

50.

polygonal numbers is the real name for this.

the formula for dimensions = 5 is

(3n² − n)/2

for dimensions = 6 it is

2n² - n

so, dimensions=5 (and therefore dividing also by 5) we get the remainders

1/5 = 0 remainder 1

5/5 = 1 remainder 0

12/5 = 2 remainder 2

22/5 = 4 remainder 2

35/5 = 7 remainder 0

51/5 = 10 remainder 1

70/5 = 14 remainder 0

92/5 = 18 remainder 2

117/5 = 23 remainder 2

145/5 = 29 remainder 0

here the pattern is 1 0 2 2 0 1 0 2 2 0 1 0 2 2 0 ...

dimensions=6 (and therefore dividing also by 6) we get the remainders

1/6 = 0 remainder 1

6/6 = 1 remainder 0

15/6 = 2 remainder 3

28/6 = 4 remainder 4

45/6 = 7 remainder 3

66/6 = 11 remainder 0

91/6 = 15 remainder 1

120/6 = 20 remainder 0

153/6 = 25 remainder 3

190/6 = 31 remainder 4

231/6 = 38 remainder 3

276/6 = 46 remainder 0

325/6 = 54 remainder 1

here the pattern is 1 0 3 4 3 0 1 0 3 4 3 0 1 0 3 4 3 0 ...

8 0
3 years ago
What happens to the volume of a rectangular prism when the length and width are double and the height is tripled
Andrei [34K]

The volume goes up by a factor of 2 * 2 * 3 = 12 times.

3 0
3 years ago
Susan earned $191.25 last week. She is paid<br> $8.50/h. How many hours did she work?
Oksanka [162]

Answer:

22.5 hours

Step-by-step explanation:

191.25 divided by 8.50 hours will get you the total amount of hours she worked

5 0
2 years ago
Read 2 more answers
Latrell took one of his friends out to lunch. The lunches cost $60 and he paid 5% sales tax. If Latrell left a 15% tip on the $6
VladimirAG [237]

Answer:

$72

Step-by-step explanation:

Cost of the lunch = $60

Sales tax = 5% of $60

= 5/100 × 60

= 0.05 × 60

= $3

Tip = 15% of $60

= 15/100 × 60

= 0.15 × 60

= $9

how much in total did he pay?

Total amount paid = cost of the lunch + sales tax + tip

= $60 + $3 + $9

= $72

Latrell paid $72 in total for the lunch

4 0
3 years ago
What binomial do you have to add to the polynomial:
marshall27 [118]

Answer:

a)  -2x^2+5xy

b)  -3y^2+5xy

Step-by-step explanation:

<u>Part (a)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

-2x^2+5xy

(2x^2+3y^2-5xy+1)+(-2x^2+5xy)

=2x^2+3y^2-5xy+1-2x^2+5xy

=2x^2-2x^2+3y^2-5xy+5xy+1

=3y^2+1

<u>Part (b)</u>

Given polynomial  :2x^2+3y^2-5xy+1

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

-3y^2+5xy

(2x^2+3y^2-5xy+1)+(-3y^2+5xy)

=2x^2+3y^2-5xy+1-3y^2+5xy

=2x^2+3y^2-3y^2-5xy+5xy+1

=2x^2+1

7 0
2 years ago
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