Question

What's the value of log2 (1/8) ?

Answer 1

$log_aa^p=p\\------\\\\log_2 ( \frac{1}{8} ) =log_28^{-1}=log_2(2^3)^{-1}=log_22^{-3}=-3\\\\Ans.\ -3$

Answer 2

Log2(1/8)=
-log2(8)=
-(log2(2))^3=
-3log2(2)
-3