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maria [59]
3 years ago
14

HELP ME PLEASEMain sequence stage occurs as a star burns through what?

Geography
1 answer:
padilas [110]3 years ago
5 0

Main sequence stars burn through hydrogen

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A magnitude-3.0 earthquake releases just over _____ times more energy than a 1.0 magnitude earthquake.
NNADVOKAT [17]
The difference between the two mentioned magnitudes is 4.
A magnitude 1 earth-quack is 10000 times bigger than a magnitude -3 earth-quack. On the other hand, it is 1000000 times stronger in terms of energy release.

Note: To calculate the difference in energy between two earth-quacks, first you calculate the difference between their magnitudes and then you raise 10 to the output you obtain.
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3 years ago
A lahar is produced whenash is blown out of a vent and onto the side of the volcanoash and other pyroclastic ejecta become satur
Pavlova-9 [17]

Answer:

  • the side of the volcanoes and other pyroclastic ejecta become saturated with water

Explanation:

  • A pyroclastic flows can generate the lahar when they are extreme ty hot and flows with the rocks bedrock. This debris mixes up with the snow met and ice and gets rapidly traveled upwards.
  • It travels rapidly down steep slopes and a larger can also be formed when a high volume of long duration of rainfall occurs after the eruption. And the volcanic landslides are mixed with water.
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2 1. Scattering cross-section of acrosol particles is 2.5E-12 m , absorption cross-section is 0.45E- .2 12 m Concentration of pa
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Answer:

T = 3.23 \times 10^{-83}

Explanation:

thickness of aerosol layer is 2.5 km

zenith angle is 40 degree

we know that

\tau = \epsilon_{ext} . h

where

\epsilon_{ext} = N.\sigma_{ext}

\epsilon_{ext} is extinction coefficient

\sigma_{ext} extiction cross section

N = Concentration

\sigma_{ext} = (2.5 + 0.45)\times 10^{-12} m^2

                     = 2.95 \times 10^{-12} m^2

\epsilon_{ext} = 2\times 10^7 \times 2.95 \times 10^{-12} m^2 \times m^{-3}

                       = 5.9 \times 10^{-5} m^{1}

\tau = 5.9 \times 10^{-5} m^{-1}  \times 2.5\times 10^3 m

        = 14.75\times 10^{-2}

transimiitance T  = e^{\frac{-\tau}{\mu}}

                       T  = e^{\frac{- 14.75 \times 10^{-2}}{cos 40}}

T = 3.23 \times 10^{-83}

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