Answer:
c. 3a^2b^11/2
Step-by-step explanation:
The applicable rule of exponents is ...
(a^b)/(a^c) = a^(b-c)
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The reflection point P' would be (-6, 8)
Let point A(-2,4) = A (X1,Y1)
point B( 1,3 )= B (X2,Y2)
point C(4,-1) = C (X3,Y3)
and point D(?, ?) = D (X4,Y4) We have to find this point
To find X4 we have to use the formula:
X2-X1=X3-X4
Now just plug in the numbers that correspond to the letters provided:
(1)-(-2)=(4)-(X4) ----> we don't know what X4 is yet, so we have to solve for it!
1+2=4-X4
3=4-X4
3-4=-X4
-1=-X4 divide both sides by -1
X4=1
Now we have to find Y4 using this formula:
Y2-Y1=Y3-Y4
Therefore,
(3)-(4)=(-1)-(Y4)
-1=-1-Y4
-1+1=-Y4
0=-Y4
So,
Y4=0
Now we have found the coordinates of the point D, which is (1,0)
Hope this helped!
5 different amount
3d 2n 1q=65cents
1d 1n 1q=40cents
2d 2n 1q=55cents
1d 2n 1g=45cents
3d 1n 1q=60cents
