Hello,
The correct answer is 52!
Hope this helps!
Brainliest?
Answer:
The second one :) Hope it helps
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Answer:
<em>C.</em> 
Step-by-step explanation:
Given

Required
Determine which binomial expansion it came from
The first step is to add the powers of he expression in brackets;


Each term of a binomial expansion are always of the form:

Where n = the sum above

Compare
to the above general form of binomial expansion

Substitute 6 for n

[Next is to solve for a and b]
<em>From the above expression, the power of (5) is 2</em>
<em>Express 2 as 6 - 4</em>

By direct comparison of

and

We have;

Further comparison gives



[Solving for a]
By direct comparison of 



[Solving for b]
By direct comparison of 


Substitute values for a, b, n and r in



Solve for 








<em>Check the list of options for the expression on the left hand side</em>
<em>The correct answer is </em>
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