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lana [24]
3 years ago
5

HELPPP NOWW You have $3000 to enclose a rectangular piece of property with a fence. The fence costs $9 per foot. A scale drawing

of the property has a length of 8 inches and a width of 7 inches. The scale is 1 in. : 12 ft. How much will it cost to enclose the property with the fence? Do you have enough money?
Mathematics
2 answers:
cluponka [151]3 years ago
6 0

You have xxxxx to xxxxxxx x xxxxxxxxxxx piece xx property with x xxxxxx The xxxxx costs xx per xxxxx x scale drawing of the xxxxxxxx xxx a xxxxxx xx x xxxxxx and a xxxxx of x inches. The scale xx 1 in. x 12 ft. How much will xx cost xx enclose xxx property with the fence? Do you have enough xxxxxx

 

1 xxxxx x 12 ft

x inches   xxxx

x x x inches x 12 xxxx inche = xx

x x 96 xx

L = xx ft

 

1 inche x 12 ft

7 inches = x

x = 7 xxxxxx x 12 ft/1 inche = 84ft

x x xx ft

x x xx xx

 

xxx much xxxx xx xxxx to enclose the xxxxxxxx with the fence?

P = Perimeter

x x 2L + 2W

x = xxxxx + xxxxx = 192 x xxx = xxx

P = xxx xx

 

 

xx * xxx ft x xxxxxx

 

xx you have xxxxxx money?

Because, $ 3,000 xx xxxx xxxx x xxxxx

xxx I xx xxx have xxxxxx money

<span>xx</span>

andrezito [222]3 years ago
6 0
$180 is how much the whole fence will cost. You have more than enough money.
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1. When Lucas dumped the coins out of his piggy bank, he noticed that there were only nickels and dimes, and the number of nicke
vaieri [72.5K]

1- The total value of the Lucas coins dumped out of his piggy bank was $ 5.

2- Franco dumped out 36 coins from his piggy bank (16 quarters and 20 nickels).

3- There is no possible solution, as neither combination gives a total of $ 10, which is the combined total of Lucas and Franco's coins.

1- Given that when Lucas dumped the coins out of his piggy bank, he noticed that there were only nickels and dimes, and the number of nickels was twice the number of dimes, to determine, if there were 50 nickels, what was the total value of the Lucas coins dumped out of his piggy bank, the following calculation must be performed:

  • Nickel = 0.05
  • Dime = 0.10  
  • N + D = X
  • N + 1 / 2N = X
  • 50 + 25 = 75  
  • 50 x 0.05 + 25 x 0.1 = X
  • 2.50 + 2.50 = X
  • 5 = X

Therefore, the total value of the Lucas coins dumped out of his piggy bank was $ 5.

2- Since when Franco dumped the coins out of his piggy bank, he noticed that there were only nickels and quarters, and the number of quarters was six more than half the number of nickels, to determine, if the total value of the coins Franco and Lucas dumped out of each piggy bank was the same, how many coins did Franco dump out of his piggy bank, the following calculation must be performed:

  • Nickel = 0.05
  • Quarter = 0.25
  • Q = 2N + 6
  • 4 x 0.25 + 6 x 0.25 = 1 + 1.5 = 2.5
  • 8 x 0.05 = 0.40
  • 2.5 + 0.4 = 2.9
  • 8 x 0.25 + 6 x 0.25 = 2 + 1.5 = 3.5
  • 16 x 0.05 = 0.8
  • 3.5 + 0.8 = 4.3
  • 10 x 0.25 + 6 x 0.25 = 2.5 + 1.5 = 4
  • 20 x 0.05 = 1
  • 4 + 1 = 5
  • 10 + 6 + 20 = 36

Therefore, Franco dumped out 36 coins from his piggy bank (16 quarters and 20 nickels).

3- Since when Callie dumped the coins out of her piggy bank, she noticed that there were only nickels, dimes and quarters, and the number of dimes was one more than twice the number of quarters, and there were half as many quarters as nickels, y the coins dumped out of Callie's piggy bank had a total value equal to that of the coins dumped out of Franco's and Lucas' piggy banks combined, to determine what was the total value of the nickels and dimes dumped out of Callie's piggy bank, the following calculation should be performed:

  • Nickel = 0.05
  • Dime = 0.10
  • Quarter = 0.25
  • (D + 1) + 1 / 2Q + N = 10
  • 1 x 0.1 + 20 x 0.1 + 10 x 0.25 + 20 x 0.05 = 2.1 + 2.5 + 1 = 5.6
  • 1 x 0.1 + 36 x 0.1 + 18 x 0.25 + 36 x 0.05 = 3.6 + 4.5 + 1.8 = 9.9
  • 1 x 0.1 + 38 x 0.1 + 19 x 0.25 + 38 x 0.05 = 3.9 + 4.75 + 1.9 = 10.55

Therefore, there is no possible solution, as neither combination gives a total of $ 10, which is the combined total of Lucas and Franco's coins.

Learn more in brainly.com/question/11096797

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