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kogti [31]
4 years ago
11

Lisa swam 6 less than four times as many laps as Amanda. Brynne swam eight more than twice as many laps as Amanda. If Lisa and B

rynne
swam the same amount of laps, how many laps did Brynne swim?
O
7 laps
O
22 laps
O
24 laps
O
16 laps
Mathematics
1 answer:
Ganezh [65]4 years ago
3 0

Answer:

22 laps

Step-by-step explanation:

Lisa swam 6 fewer laps than four times of Amanda's laps.

Hence, L = 4A - 6

Again, Brynne swam eight more than twice as many laps as Amanda.

Hence, B =2A + 8

If Lisa and Brynne swam the same amount of laps, then  

L = B  

⇒ 4A - 6 = 2A + 8

⇒ 2A = 14

⇒ A = 7 laps

So, B = 2A + 8 = 2(7) + 8 = 22 laps

Therefore, Brynne swam 22 laps. (Answer)

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Answer:

Number of free throws = 155,

Number of two-points field goals= 168

Number of two-points field goals= 124

Step-by-step explanation:

Let x,y, and z be the numbers of free throws, two-point field goals and three-point field goals she made.

As she scored a total of 863 points, so

x+2y+3z=863...(i)

As the number of​ two-point field goals  that Rebecca made was 80 less than double the number of​ three-point field goals she made, so

2z-y=80

Or y=2z-80...(ii)

As the number of free throws​ (each worth one​ point) she made was 13 less than the number of​ two-point field goals she made, so

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Now, put the values from equation (ii) and (iii) to equation (i), we have

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From equation (ii)

y=2x124-80=168

and from equation (iii)

x=2x124-93=155.

Hence, the number of free​ throws, two-point field​ goals, and​ three-point field goals Rebecca Smith made during the 2006 regular season are 155, 168, and 124 respectively.

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