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4 years ago

Brad jarred 12 liters

Mathematics

2 answers:

GalinKa [24]4 years ago

5 0

18 jars

12 divided by 2 is 6.

We know each day Brad jars 6.

6 x 3 = 18

olga_2 [115]4 years ago

3 0

Answer:

18 liters

Step-by-step explanation:

We can use ratios to solve

12 liters x liters

----------- = -----------

2 days 3 days

Using cross products

12 *3 = 2x

36 =2x

Divide by 2

36/2 = 2x/2

18 =x

18 liters

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3 years ago

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A student was assigned to read a book over 5 days. On the first day, she read 25 pages. On the second day she read 45 pages, on

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7 0

3 years ago

Please someone help me

ruslelena [56]

Answer:

r = 0.046212737

Step-by-step explanation:

A = 14,400 (what your investment originally is)

P = 7,200 (what you want your investment to be)

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8 0

3 years ago

Read 2 more answers

Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different

N76 [4]

Answer:

(a) As time increases, the amount of water in the pool increases.

11 gallons per minute

(b) 65 gallons

Step-by-step explanation:

From inspection of the table, we can see that as time increases, the amount of water in the pool increases.

We are told that Ann adds water at a constant rate. Therefore, this can be modeled as a linear function.

The rate at which the water is increasing is the rate of change (which is also the slope of a linear function).

Choose 2 ordered pairs from the table:

$\textsf{let}\:(x_1,y_1)=(8, 153)$

$\textsf{let}\:(x_2,y_2)=(12,197)$

Input these into the slope formula:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11$

Therefore, the rate at which the water in the pool is increasing is:

11 gallons per minute

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

$y-y_1=m(x-x_1)$

$\implies y-153=11(x-8)$

$\implies y-153=11x-88$

$\implies y=11x-88+153$

$\implies y=11x+65$

When Ann had added no water, x = 0. Therefore,

$y=11(0)+65$

$y=65$

So there was 65 gallons of water in the pool before Ann starting adding water.

3 0

3 years ago

Read 2 more answers