3 years ago

Find the equation of the circle whose center is at (4, 5) and that contains (13, −1).

1 answer:

3 0

The equation of circle is
(x-4)^2+(y-5)^2=R^2
if you replace the (13, -1) with x and y the R^2 will be 117
(x-4)^2+(y-5)^2=117

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